Three class definitions and a main function are given below: class X { public: }; class Y public X { public: }; X() { a = 10; b = 20; } short a; int b; } Y(): X() { c = 30; d = 40; } short c; short d; int main() { X X; Y Yi X z = y; return 0; Three objects are created in main. Draw each object's memory structure (x, y, z) in the space above assuming that object x's memory address is 0x7fff5d8f9528, y's memory address is 0x7fff5d8f9518 and z's memory address is 0x7fff5d8f9510. For each class' member variables, write each of their memory address location.
Three class definitions and a main function are given below: class X { public: }; class Y public X { public: }; X() { a = 10; b = 20; } short a; int b; } Y(): X() { c = 30; d = 40; } short c; short d; int main() { X X; Y Yi X z = y; return 0; Three objects are created in main. Draw each object's memory structure (x, y, z) in the space above assuming that object x's memory address is 0x7fff5d8f9528, y's memory address is 0x7fff5d8f9518 and z's memory address is 0x7fff5d8f9510. For each class' member variables, write each of their memory address location.
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
f18
In c++
Expert Solution
Step 1
In this question, it is asked to calculate the object and member variable's memory address with c++ code.
The code is given below with the necessary comments and all printing statements.
Every system will have a different result of the memory address but by comparing the results the values can be calculated.
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