Three charges ql = +3µC, q2%=- 4 LC and a negative q3 is placed 3 cm from each other to form an equilateral triangle as shown. Determine the value of the unknown charge if the force between charge 2 and 3 is equal to 240N. Determine the total force (magnitude and direction) acting on charge ql. q1 q2

A charge q1 equal to 0.500 μC is at the origin, and a second charge q2 equal to 0.800 μC is on the x axis at 4.00 cm. Find the force (magnitude and direction) that 0.500-μC charge exerts on 0.800-μC charge. Enter a positive value if the force acts in the +x direction and a negative value if the force acts in the -x direction. (Express your answer to three significant figures.) Find the force (magnitude and direction) that 0.800-μC charge exerts on 0.500-μC charge. Enter a positive value if the force acts in the +x direction and a negative value if the force acts in the -x direction. (Express your answer to three significant figures.) How would your answers change if q2q2 were -0.800 μC? The magnitudes of the forces would rise, while the directions would be the same.   The magnitudes of the forces would rise and the directions would change to opposite.   The directions of the forces would change to opposite, while the magnitudes would be the same Answers would be the same.

Two charges +1 μC and +13 μC are placed along the x axis, with the first charge at the origin (x = the second charge at x = +1 m. Find the magnitude and direction of the net force on a -8 nC charge 0) and when placed at the following locations below. Overall Hint a. halfway between the two charges: magnitude of force is direction is Select an answer b. on the axis at x = -0.5 m: magnitude of force is is Select an answer c. at the coordinate (x, y) = (1 m, 0.5 m) (half a meter above the +13 μC charge in a direction perpendicular to the line joining the two fixed charges): Hint for (c) Magnitude of force is degrees below -x axis. mN, and the direction is mN, and the mN, and the direction

A positive point charge Q is located at x-a and a negative point charge -Q is at x = -a. A positive charge q can be placed anywhere on the y-axis. Find an expression for (FX, the x -component of the net force on q. Give your answer in terms of Q, q, a, y and constant K. Do your assessment by looking at (F)x when y = 0. net net