Answered: Three blocks with masses m1 = 2.3 kg,…

An Introduction to Physical Science

14th Edition

ISBN:9781305079137

Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres

Publisher:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres

Chapter1: Measurement

Section: Chapter Questions

Problem 5FIB

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Question

Three blocks with masses m1 = 2.3 kg, m2 = 6.2 kg and m3 = 1.0kg are connected by a light string that passes over a light pulley as shown in the figure below. The table on which blocks m1 and m2 are lying is frictionless. The blocks are released from rest and allowed to move freely.

A. Draw the free-body diagrams for the blocks and write down Newton's second law of motion for each one separately.

B. Find the acceleration of the system. C. Find the tension forces T1 and T2 acting in the strings.

ension forces 1₁
1₂ acting
m₁
T
m₂
igs.
T₂
m3

Expert Solution

Step 1

Given:

m₁ = 2.3 kg

m₂ = 6.2 kg

m₃ = 1 kg

(a).

For m₁ and m₂ forces are balanced in vertical direction i.e,

$\Rightarrow N_{1} = m_{1} g$

$\Rightarrow N_{2} = m_{2} g$

Let the acceleration of the system be 'a'

Now applying newton's second law of motion

For m₁:

$\Rightarrow T_{1} = m_{1} a \underset{}{\to} (1)$

For m₂:

$\Rightarrow T_{2} - T_{1} = m_{2} a \underset{}{\to} (2)$

For m₃:

$\Rightarrow m_{3} g - T_{2} = m_{3} a \underset{}{\to} (3)$

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