This one is "charged" with an aminoacid. The specific sequence in the bottom is called the "Anticodon" which will be a perfect match to a codon in the transcript. Let's focus on this tRNA for Pro:
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- The tRNA anticodon sequence 3’GAG 5’ is charged with the amino acid leucine. This anticodon may pair with both 5’ CUC 3’ and 5’ CUU 3’. Which of the following is consistent with this phenomenon? 1. The information provided is not accurate since only the 5’ CUC 3’ codon can complementary base pair with the 3’ GAG 5’ anticodon 2. This feature allows for the genetic code to be degenerate 3. This feature allows for the genetic code to be overlapping 4. This feature is commonly associated with tautomeric shifts 5. This feature causes a change in the encoded amino acidWrite the sequence of the mRNA molecule synthesized from a DNA template strand having the sequence 5'-ATTACAGGCGGT-3' 5'- UAAUGUCCGCCA Incorrect Write the amino acid sequence encoded by the mRNA base sequence 5'-GAGUUAGUUUGUAAGUGC-3' Assume the reading frame starts at the 5' end. Refer to the codon table . Amino acid sequence: Glu-Leu-Val-Cys-Lys-Cys What is the sequence of the polypeptide formed on addition of poly(UUAC) to a cell-free protein-synthesizing system that does not require a start codon? Enter an amino acid sequence of four amino acids using the three-letter abbreviations. Polypeptide sequence: Poly( -3' Glu-Leu-Val-Cys-Lys-CysShown here is a tRNA for tryptophan. Which of the locations on the tRNA accommodates looser base-pairing rules? H part 2 H₂N-C N H CH₂ -C || CH codons C 3 1 2 35' Choose one: IIIIIIIbase-pairing UGG anticodon in tRNA 5' Choose one: O A. site 3 OB. site 1 OC. All of the sites maintain strict base-pairing rules. OD. site 2 3' Using the genetic code here, determine the amino acids that a polynucleotide of UC would code for. AGA UUA AGC AGG AGU UUG CUA GUA GCA CGA GCC CGC GGA GGC CCA UCA ACA CCC UCC ACC AUA CUC GUC GCG CGG GAC AAC UGC GAA CAA GGG CAC AUC CUG AAA UUC CCG UCG ACG UAC GUG GCU CGU GAU AAU UGU GAG CAG GGU CAU AUU CUU AAG AUG UUU CCU UCU ACU UGG UAU GUU Lys Met Phe Pro Ser Thr Trp Tyr Val KM FPS T W Y V amino Ala Arg Asp Asn Cys Glu Gin Gly His lle Leu DN E QGHIL acids A R с O A. Ser, His O B. Leu, Ser OC. Phe, Leu O D. His, Thr codon in mRNA UAA UAG UGA stop
- Using the Genetic Code Table in Figure 1.3, what is the proper sequence of amino acids in the polypeptide chain based from the given codons of MRNA (3' AAU GCC AGU GGU 5')? * U UUU Phe UCU) UC UCA UCG UAU] UAC Tyr UAA Stop UGA Stop A UAG Stop UGG Trp G UGU U UUC) UGC Cys Ser UUA Leu UUGJ CU) CCU CAU1 CGU His CUC CAC CAA CGC CC Leu CCA Pro Arg CUA CGA A Gin CUG) CG CAG CGG G AUU) ACU) AGU AAU1 Asn AAC, Thr AAA1 U AGC }Ser č A G AUC lle ACC A AUA J ACA AGA AUG Met ACG, AAG}Lys AGG Arg GGU GUU) GUC Val GCU) GCC GCA GCG J GAU1 Asp GACI Ala GGC GGA GGG ) G GUA Gly GAA1 GAG) A Glu GUG) G Figure 1.3 Alanine, Serine, Glycine, Asparagine Serine, Glycine, Asparagine, Alanine Glycine, Asparagine, Alanine, Serine Asparagine, Alanine, Serine, GlycineSeveral experiments were conducted to obtain information about how the eukaryotic ribosome recognizes the AUG start codon. In one experiment, the gene that encodes methionine initiator tRNA (tRNAiMet) was located and changed; specifically, the nucleotides that specify the anticodon on tRNAi Met were mutated so that the anticodon in the tRNA was 5′ –CCA–3′ instead of 5′ –CAU–3′. When this mutated gene was placed in a eukaryotic cell, protein synthesis took place, but the proteins produced were abnormal. Some of these proteins contained extra amino acids, and others contained fewer amino acids than normal. a. What do these results indicate about how the ribosome recognizes the starting point for translation in eukaryotic cells? Explain your reasoning. b. If the same experiment had been conducted on bacterial cells, what results would you expect? c. Explain why some of the proteins produced contained extra amino acids while others contained fewer amino acids than normalWhich of the triplets below is a possible anticodon for a tRNA that transports Leucine (Leu) to a ribosome? Second letter C UGU cys UCU1 UCC UCA UCG UAU Tyr UACS Ser UAA Stop UGA Stop A UAG Stop UGG Trp UUU UGCS Phe UUC U UUA UUG FLeu CAU HiS CGU] CUU CUC Leu CCU ССС CCA CCGJ CACS CGC Arg CGA CAA GIn Pro C CUA CUG J CAG S CGG AUU AUC lle AUA AAU Asn AGU ser ACU АСС Thr ACA AAC AAA ys AGA Arg AAG J AGC AUG Met ACG Lys AGG J GUU GUC CUA Val GAU ASP GCU GACJ GCC FAla GGU] GGC CGA Gly CCA C CAA M UCAG Third letter UCAG UCAG First letter
- What will be the overall anti-codon sequence in tRNA for this mRNA? 5’-GUAGCCUUAUCUAGCGAUCACCGUCCGUAUUACUAGUGGCCAGACUCUUUUCACCAUGUAUAGUUG-3’if the codon for Leucine is 5'-CUG-3'. what is the sequence of the corresponding anticodon on the tRNA-Leu? 5'-CUG-3' 3'-GAC-5' 3'-CUG-5' 5'-GAC-3'Several experiments were conducted to obtain information about how the eukaryotic ribosome recognizes the AUG start codon. In one experiment, the gene that encodes methionine initiator tRNA (tRNAiMet) was located and changed; specifically, the nucleotides that specify the anticodon on tRNAiMet were mutated so that the anticodon in the tRNA was 5′ –CCA–3′ instead of 5′ –CAU–3′. When this mutated gene was placed in a eukaryotic cell, protein synthesis took place, but the proteins produced were abnormal. Some of these proteins contained extra amino acids, and others contained fewer amino acids than normal. Q. If the same experiment had been conducted on bacterial cells, what results would you expect?
- Several experiments were conducted to obtain information about how the eukaryotic ribosome recognizes the AUG start codon. In one experiment, the gene that encodes methionine initiator tRNA (tRNAiMet) was located and changed; specifically, the nucleotides that specify the anticodon on tRNAiMet were mutated so that the anticodon in the tRNA was 5′ –CCA–3′ instead of 5′ –CAU–3′. When this mutated gene was placed in a eukaryotic cell, protein synthesis took place, but the proteins produced were abnormal. Some of these proteins contained extra amino acids, and others contained fewer amino acids than normal. Q. What do these results indicate about how the ribosome recognizes the starting point for translation in eukaryotic cells? Explain your reasoning.An mRNA transcript has the following complete sequence: 5'-AUGCCUACGUUACGGACC-3' Rewrite the sequence to give it a missense mutation. Circle/highlight the mutation. Explain how your specific mutation would affect the formation and structure of the 2nd (middle) Base of a Codon 1st U CA G 3rd Base Base UUU Phe UUC Phe UUA Leu UUG Leu UCU Phe UCC Phe UCA Leu UCG Leu UAU Tyr UAC Tyr UAA STOP UAG STOP UGU Cys UGC Cys UGA STOP UGG Trp protein. U CUU Leu CUC Leu CUA Leu CUG Leu CCU Pro ССС Pro CCA Pro CCG Pro CAU His CAC His CAA Gln CAG Gln CGU Arg CGC Arg CGA Arg CGG Arg AGU Ser AGC Ser AGA Arg AGG Arg AAU Asn AAC Asn AUU lle AUC lle AUA lle AUG Met ACU Thr ACC Thr ACA Thr ACG Thr A AAA Lys AAG Lys GUU Val GUC Val GUA Val GUG Val GCU Ala GCC Ala GCA Ala GCG Ala GAU Asp GAC Asp GAA Glu GAG Glu GGU Gly GGC Gly GGA Gly GGG Gly UCAGUse this mRNA coding sequence as your starting point. This sequence begins with a start codon and ends with a stop codon, so it is only looking at the region of DNA that directly encodes a protein sequence. 5’-AUGCACAAAUUAGAGUACCCCCCAGGAAGGUAG-3’ Make the following mutation in this sequence by changing/adding/removing only one nucleotide. Make the mutation easy to see (a different color, circled, something like that) A frameshift mutation