This new estimate for V2 substituted back to the equation will produce the second estimate: V 2.2 1 = 0.3603-146.3° -(1.9612/101.3°)(120°) 1.9612-78.8° 0.8797/+8.499° =0.8412-8.499° The third iteration will be V 2.3 1 0.3603-146.3° (1.9612/101.3°)(120°)] 1.9612-78.8° 0.8412/+8.499° = 0.8345-8.962° The fourth iteration will b 1 V 2,4 = 0.3603-146.3° -(1.9612/101.3°)(120°) 1.9612-78.8° 0.8345/+8.962 = 0.8320-8.962°

Consider a circuit that contains two switches as shown in Figure Q4. The switch on the right-hand side can be connected to nodes S₁ or S₂. The two switches operate as follows: ➤ If this right-hand switch is connected to node S₁, the switch labelled S3 is in the open position. If the right-hand switch is connected to node S₂, the switch labelled S3 is in the closed position. Both switches switch instantaneously and simultaneously. R = 20 ΚΩ C = 0.25 nF HE +21 S3 L=1 mH R, = 20 ΚΩ S₁ 1S₂ AS = SA iL Figure Q4 a) After being connected to node S₂ for a very long time, the right-hand switch is connected to node S₁ at t = 0. Derive a differential equation for the current through the inductor iz(t) and find an expression for iz(t) for all times > 0. Use numerical values for all known circuit elements ONLY in the final expression of iz(t) b) Following the events outlined in part a), the right-hand switch is connected to node S₂ at t = 5 µs. Derive a differential equation for the current through…

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We have a square pyramid in which all eight edges are perfect 1-ohm resistors. Find the equivalent resistance between any two vertices.