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This karyotype is from a baby that was born alive but died shortly after birth. What condition is observed from this karyotype?
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- C UUU UUC Phe UUA UCU) UCC UCA UAU UAC Tyr UGU UGC Cys Ser UAA Stop UGA Stop A UAG Stop UGG Trp UUG FLeu UCG CUU CUC CCU] СС CAU1 CAC САC His САА Gln CGU CGC Arg Leu Pro CUA CUG ССА CGA CUG J CCGJ Which of the following tRNA anticodons could theoretically base pair effectively with the codons 5'-AAU-3' and 5'-AAC-3' through third-base CAG, CGG AGU AAUASN AGC AUU AUC File A AUA ACU АСС АСА AAC FAsn AAA Ser C Thr AGA Arg A AUG Met ACG AAG Lys AGG GCU] GCC GCA GCG GGU GGC Gly GGA GAU1 GUU GUC GUA GUG Asp GACJ GAA C Val Ala A GAG Glu GGG wobble? 5'-GGG-3' OI. 5'-AUG-3' II. 5'-GUU-3' I. 5'-CAT-3' IV. 5'-AAA-3 V. Third letter UCAG UUAG A, First letterCould you please help me part d on this problem? Thank you!PAYS- DASO บบบ 1 UUC UUA UUG CUU CUC CUA CUG U '} GUU GUC GUA GUG PHE LEU AUU AUC AUA AUG MET or START LEU ILE VAL UCU UCC UCA UCG CCU CCC CCA CCG ACU ACC ACA ACG GCU GCC GCA GCG Second base SER PRO THR ALA UAC} TYR UAA UAG } STOP CAU CAC CAA CAG} AAU AAC AAA AAG J HIS GLN ASN LYS GAU ASP GAC GAG GLU UGU CYS UGC UGA} STOP UGG TRP CGU CGC CGA CGG AGU AGC AGA AGG G GGU GGC GGA GGG ARG SER ARG GLY SCAR SCAG А
- d/e/1FAIPQLSCDH_No2]MEaHUdrt5NWa2uY6AaKa7Bhy4xfhwplF-CsVAbyA/formResponse M Gmail YouTube O Maps Which phrase best describes a human with the chromosomes represented in the karyotype below? * 1 3 4 5 X r8 K* XX从 6. 8 9. 10 X* ** ** 11 12 13 14 15 16 17 18 19 20 XX 44 21 22 XX O A female who exhibits Down syndrome A male who exhibits Down syndrome O A female who does not exhibit Down syndrome O A male who does not exhibit Down syndrome 8.Aa Po AaBbCcDc AaBbCcDdEe AaBbCcDdE AaBbCcDdE AaBbCcDdE BIUVab x, x A ev A 三==|這、|の Caption Emphasis Heading 1 Heading 3 Heading 4 Style Pane (a) Complete the table, using a letter D, R or B, to show whether each statement applies to: Fo DNA only (D) TA2G – Completed forms must be available for Open Awards external moderation purposes. Page 6 of 15 > T | RNA only (R) Both DNA and RNA (B) Statement D or R or B Contains thymine Contains ribose Consists of two chains connected to each other with hydrogen bonds Has a sugar-phosphate backbone Has four different nitrogenous bases Contains a pentose sugar Is found in the nucleus and cytoplasm English (United Kingdom) Focus 目民 2490 words +1세 메 B D C F E ㅁㅁㅁ -40-404 | 1602 40000 H ㅁㅁㅁ ㅅㅁㅅㅁㅅㅁ
- Consider the mRNA sequence below. Assume that the following mRNA segment has been translated. 5'-UACCGAAUGUCU-3' Note for numbers 1 and 2: Use the three-letter abbreviation of amino acid; separate amino acids with a hyphen: do not include the stop codon. Example: ala-cys-glu 1. Using the table of the genetic code, determine the sequence of amino acids. 2. If mutation occurs by substitution of the 12th nucleotide with cytidine-5'- monophosphate, what is the resulting amino acid sequence? 3. What type of mutation occurred? Choose from same sense, missense and non-sense.9 Genet x K Kami 9 Point x K point- x 9 Band, X S Week x 9 Geog x My Qu X STI In X > (2 x R Read X Discu X A web.kamihq.com/web/viewer.html?file=https%3A%2F%2Ftuscaloosacity.schoology.com%2Fattachment%2F1716642933%2Fsource%2F775235e0ba17ab191f792e5f.. K * : = 3+Branches+of+Go. O STI InformationNo. E Schubert = Pod 2 7th Master S. Other bookmarks Каmi Student Upgrade O O A My Drive Kami Export - Scan Feb 26, 2021.pdf A Turn In 100% JT Use the following information for questions 10-12: In dogs, the gene for fur color has two alleles. The dominant allele (F) codes for grey fur and the recessive allele (f) codes for black fur. 10) The female dog is heterozygous. The male dog is homozygous recessive. What is the chance their offspring have grey fur? T 14 - 11) The female dog has black fur. The male dog has black fur. What is the chance their offspring has a heterozygous genotype? 12) The female dog is heterozygous. The male dog is heterozygous. What is the chance their offspring is…ory X Gakg614 micro x Mail - Kayli Je X Google Docs ×/d/1n5NtidRwTwUzcDkDPi5Z9P_SHPZ91A-XH-pfftLbhNc/edit (1) O pols Add-ons Help Last edit was seconds ago BIUA ミ: 12 + ext Calibri I|1 6 I 2 Section 5: Trihybrid cross and Laws of probability For a trihybrid cross, in which inheritance of alleles for three genes is tracked, drawing a Punnett square that combines all three genes may not be practical. Instead the laws of probability may be used. The product law of probabilities says that when alleles for separate genes segregate independently, we can figure out the probability of a particular combined genotype by multiplying the probability of the alleles for each gene. 13. We cross a homozygous tall pea plant with yellow, round seeds to a homozygous dwarf pea plant with green, wrinkled seeds. All the F1 offspring are all tall plants with yellow, round seeds. a. What are the expected F2 ratios (use fractions) of tall and dwarf plants? b. What are the expected F2 ratios (use fractions) of yellow and green seeds? C. What are the expected F2…d/1n5NtidRwTwUzcDkDPi5Z9P SHPZ9IA-XH-pfftLbhNc/edit 1) @ Is Add-ons Help Last edit was 15 minutes ago | Calibri в I UA 12 + 3I | II 6 1 I 7. Construct a Punnett square for a cross between two heterozygous pea plants with violet flower color. a. What genotypes would you expect in the offspring? b. What percentage or ratio of each genotype would you expect in the offspring? !!!Hi, I’m having problem how to find the chi- square analysis I need to learn how to do it please, I been trying but is very hard for mes thank youSEE MORE QUESTIONS