The formula of the test is as follows: X2 = E(dle) X2 = chi-square %3D E= sum of d = difference between expected and observed results (most often termed the deviation) e = expected results Example In the cross of wild-type by vestigial wing, a 3:1 ratio is expected. Thus, if a student counts 160 flies, 40 are expected to have vestigial wings, while 120 are expected to have long wings, but if a student counts 44 vestigial-winged flies and 116 long-winged flies, then the value for the chi-square test would be as calculated in the Table 1. Note: You will have four different phenotype combinations tolanalyze. Table 1: Calculation of Chi-Square - X2 Expected Number (e) Partial Chi-Square dle Phenotype Observed Number Difference (d) Vestigial Wing 44 40 4 16 16/40 = 0.400 Long Wing 116 120 4 16 16/120 = 0.133 E(dle) = 0.533 X2 = 0.533
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- Activity 4 Identification of phenotype of known genotype The characteristic of the color of the red tomato fruit (R) is dominant over the characteristic of the yellow color (r) The characteristic of the color of white flowers (W) is dominant over the characteristic of the color of the yellow flowers (w), and the characteristic length of the stem of the plant (T) is dominant over the short characteristic (t) If a red fruit plant with yellow and long-stemmed flowers is crossed, with anotheryellow, white-flowered and short-stemmed plant, knowing that the dominant characteristic is pure. What is the phenotype of individuals of the resulting generation?11:41 Cancel Markup Done Name: Date: Monohybrid practice problems In pea plants, the traits below exhibit the following dominance patterns: Recessive Expression: Wrinkled Dominant Expression: Round Purple |Yellow Inflated Green Trait: 1. Seed shape (R) 2. Flower color (P) 3. White Green Constricted Yellow Terminal Short Color of seed coat (Y) Form of ripe pods (I) 4. 5. |Color of unripe pods (G) 6. Position of flowers (A) 7. Length of stem (T) Axial Tall Record the genotypes for pea plants with the following descriptions (The first one has been done for you: 1. а. дg A plant with yellow pods A planteozygous for ereen pods С. A plant homozvaoue ta vellow seeds A plant with white flowers A plant with areen seeds 2. Complete the Punnett Square showing the cross between a pea plant with pure round seeds and a plant with wrinkled seeds. Summarize the phenotypes and genotypes for the offspring. Parental cross Genotypic Percentages: Phenotypic Percentages: 3. A pea plant with pure yellow…11:42 Cancel Markup Done Name: Date: Monohybrid practice problems In pea plants, the traits below exhibit the following dominance patterns: Recessive Expression: Wrinkled Dominant Expression: Round Purple |Yellow Inflated Green Trait: 1. Seed shape (R) 2. Flower color (P) 3. White Green |Constricted Yellow Terminal Short Color of seed coat (Y) Form of ripe pods (I) 4. 5. |Color of unripe pods (G) 6. Position of flowers (A) 7. Length of stem (T) Axial Tall Record the genetvnes f-Der-- = foltrawino deserintins (The first one has been done for you): а. дg A plant with yellow poás- EplancteOZygous for ereen pods N 0)e Owers С. A plant homozvaoue ycilow seeds A plant with white flowers TA piamt wilh areen seeds. Complete the Punnett Square showing the eress between a pea plant with pure round seeds and a plant with wrinkled seeds. Summanze the phenotypes and genotypes for the offspring. Genolynic PorcentadCS. Parental cross PhenolypicPerceniageS 3A pea plant with pure velow seeds is erossed…
- Practice question: I understand how the F1 progeny is found (by punnett square), but I do not get how they were able to get the F2 progeny (can i use a punnet square? How do i find these results?)be holding online office hours Tuesday morning. Background to Problems 1 and 2. When a fly (Drosophila) strain with round, brown eyes was crossed to a different strain with kidney-shaped, red eyes, all F1 flies had eyes that were round and red. When these Fi flies were test crossed (i.e., mated to a suitable test strain), there were four distinct eye phenotypes observed in the F2, all at approximately the same frequency (i.e., ~ 25% each), namely: 1) round & red; 2) round & brown; 3) kidney-shaped & red; and 4) kidney-shaped & brown. 1) How many different genes (each with two alleles) control the eye phenotype in this example? 2) What was the phenotype of the test strain flies?Horizontal sequence :RIVL Vertical sequence:FMK Scoring rules: g/o = -3, g/e = -1, match or mismatch - from PAM250 substitution matrix below. NW algorithm. 1. Complete the scoring matrix. Scoring matrix with PAM250 scores: R I V L F M K 2. Set up, initialize and complete the NW matrix. 3. Retrace, align and score alignment(s). Use the arrows and circles for the matrix and path(s). R I V L F M K Align and score all optimal alignments here. PLZ the arrows and circles for the matrix and path(s) AND SHOW ALL possible Alignment Here the following…
- Genetic Problems Read the following genetic problems, and then complete the activities and questions for each problem 1. In the pea plant, the green pod color allele is dominant to the yellow pod color allele. o Set-up a monohybrid cross between a pea plant that is heterozygous and a true-breeding yellow pod pea plant. o What percentage of the offspring produced from this cross would you expect to have yellow pods? 2. Within a mouse population, the black fur allele (B) is dominant to the white fur allele (b) and the short whisker allele (S) is dominant to the ngs long-whisker allele (s). o A heterozygous black-furred short-whiskered mouse is crossed with a homozygous white-furred long-whiskered mouse. o What percentage of the offspring will be black-furred with long whiskers? 3. A physician is examining the blood types of children from a family. o Child 1 has blood type AB, Child 2 has blood type B, Child 3 has blood type B, and Child 4 has blood type A. o Based on the phenotypes of…3.17 The accompanying pedigree and gel diagram phenotypes of the progeny, and in what propor- show the phenotypes of the parents for an SSRP that has multiple alleles. What are the possible thdt that has multiple alleles. What are the possible phenotypes of the progeny, and in what propor. tions are they expected? bobiah of 152 148 144 140 Be %3D eekinHorizontal sequence :VIRL Vertical sequence:MKF Scoring rules: g/o = -3, g/e = -1, match or mismatch - from PAM250 substitution matrix below. NW algorithm. 1. Complete the scoring matrix. Scoring matrix with PAM250 scores: V I R L M K F 2. Set up, initialize and complete the NW matrix. 3. Retrace, align and score alignment(s). Use the arrows and circles for the matrix and path(s). V I R L M K F Align and score all optimal alignments here. PLZ the arrows and circles for the matrix and path(s) AND SHOW ALL possible Alignment
- Instructions: Answer the following problem using the punett square and identify its Genotypic ratio and Phenotypic ratio. 1. A homozygous round-seeded plant (RR) is crossed with a homozygous wrinkle-seeded plant (rr). What is the phenotypic and genotypic ratio of their offspring? Genotypic Ratio Phenotypic Ratio- 2. A heterozygous green-colored pod (Gg) is crossed with a yellow-colored pod (gg). Predict the Genotypic and Phenotypic ratio of their offspring. Genotypic Ration Phenotypic Rationquare, PROBLEMS FOR PRACTICE: In your responses show your work (calculations/explanation) as well as place a box around eone lo Vilidedong teerigiri er final answer. 1. What is the probability of an organism with the following genotype A a Bb CcDd producing a gamete with the following allele combination a BC d ? 2. What is the probability of an organism with the following genotype A a B b C cDd producing a gamete with the following allele combination a b cd? eniwi Isoitnebl.8 3 What is the probability of an organism with the following genotype A a B b C C producing a gamete taidw) no9bas mega emse 9di mol beauboma ritiw ainensg owl 11,alleo pge ets bns mega els16q92 moit beubong ens niwi Ismstsil aseertw with the following allele combination A b C ? Uld ruiw vod niwi ano eauboiq (lisu Insnimob s) 29ys nwoid Seeve auld eved liw erd Isoinebi ai niwi 1erdto erlt (e Seeve auld eved lliw ede to erd,lemelst ai niwi rertio erli 11(C uld sdi timage liw Iemelsil.zl.niwtjerto eni C11:42 ll Cancel Markup Done Name: Date: Monohybrid practice problems In pea plants, the traits below exhibit the following dominance patterns: Recessive Expression: Wrinkled Dominant Expression: Round Purple |Yellow Inflated Green Trait: 1. Seed shape (R) 2. Flower color (P) 3. White Green |Constricted Yellow Terminal Short Color of seed coat (Y) Form of ripe pods (I) 4. 5. |Color of unripe pods (G) 6. Position of flowers (A) 7. Length of stem (T) Axial Tall Record the genetvnes f-Der-- = foltrawino deserintins (The first one has been done for you): а. дg A plant with yellow poás- EplancteOZygous for ereen pods N 0)e Owers С. A plant homozvaoue ycilow seeds A plant with white flowers TA piamt wilh areen seeds. Complete the Punnett Squae showing the eress between a pea plant wth pure round seeds and a plant with wrinkled seeds. Summanze the phenotypes and genotypes for the offspring. Genolynic PorcentagCS. Parental cross PhenolypicPerceniageS 3. A pea plant with pure yellow seeds is…