The formula of the test is as follows: X2 = E(dle) X2 = chi-square %3D E= sum of d = difference between expected and observed results (most often termed the deviation) e = expected results Example In the cross of wild-type by vestigial wing, a 3:1 ratio is expected. Thus, if a student counts 160 flies, 40 are expected to have vestigial wings, while 120 are expected to have long wings, but if a student counts 44 vestigial-winged flies and 116 long-winged flies, then the value for the chi-square test would be as calculated in the Table 1. Note: You will have four different phenotype combinations tolanalyze. Table 1: Calculation of Chi-Square - X2 Expected Number (e) Partial Chi-Square dle Phenotype Observed Number Difference (d) Vestigial Wing 44 40 4 16 16/40 = 0.400 Long Wing 116 120 4 16 16/120 = 0.133 E(dle) = 0.533 X2 = 0.533

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Hi, I’m having problem how to find the chi- square analysis I need to learn how to do it please, I been trying but is very hard for mes thank you
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Page 2 of 8
The formula of the test is as follows:
x2 =E(dPle)
X2 = chi-square
%3D
2 = sum of
d = difference between expected and observed results (most often termed the deviation)
e = expected results
Example
In the cross of wild-type by vestigial wing, a 3:1 ratio is expected. Thus, if a student counts 160 flies,
40 are expected to have vestigial wings, while 120 are expected to have long wings, but if a student
counts 44 vestigial-winged flies and 116 long-winged flies, then the value for the chi-square test would
be as calculated in the Table 1.
Note: You will have four different phenotype combinations tolanalyze.
Table 1: Calculation of Chi-Square - X2
Partial Chi-Square
dle
Phenotype
Observed
Expected
Number (e)
Difference (d)
Number
Vestigial Wing
44
40
4
16
16/40 = 0.400
Long Wing
116
120
4
16
16/120 = 0.133
E(dle) = 0.533
X2 = 0.533
BIO 13
Transcribed Image Text:Instructions white Eyed Q Search Page 2 of 8 The formula of the test is as follows: x2 =E(dPle) X2 = chi-square %3D 2 = sum of d = difference between expected and observed results (most often termed the deviation) e = expected results Example In the cross of wild-type by vestigial wing, a 3:1 ratio is expected. Thus, if a student counts 160 flies, 40 are expected to have vestigial wings, while 120 are expected to have long wings, but if a student counts 44 vestigial-winged flies and 116 long-winged flies, then the value for the chi-square test would be as calculated in the Table 1. Note: You will have four different phenotype combinations tolanalyze. Table 1: Calculation of Chi-Square - X2 Partial Chi-Square dle Phenotype Observed Expected Number (e) Difference (d) Number Vestigial Wing 44 40 4 16 16/40 = 0.400 Long Wing 116 120 4 16 16/120 = 0.133 E(dle) = 0.533 X2 = 0.533 BIO 13
F, Results After 14 Days.
Transcribed Image Text:F, Results After 14 Days.
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