This is what I have so far 1. Too many arguments. #include Void simple(); Int main() { Int n; simple(1,2,3,4,5,6,7,8,9,10,11,12); Return0; } Void simple(int n){ printf(“%d”,n); } What does this do? This code prints the first argument passed to the simple function called. That is (1). Does the extra argument break the code? No, the extra argument does not break the code as the remaining argument are ignored by the function. Which argument(s) gets printed? The arguments are printed in the order they are called in the function. Here, the argument to be passed first is 1 and that is printed. The first argument is printed. Why? This is because the remaining arguments are evaluated by the function and then ignored. 2. Too few parameters
This is what I have so far 1. Too many arguments. #include Void simple(); Int main() { Int n; simple(1,2,3,4,5,6,7,8,9,10,11,12); Return0; } Void simple(int n){ printf(“%d”,n); } What does this do? This code prints the first argument passed to the simple function called. That is (1). Does the extra argument break the code? No, the extra argument does not break the code as the remaining argument are ignored by the function. Which argument(s) gets printed? The arguments are printed in the order they are called in the function. Here, the argument to be passed first is 1 and that is printed. The first argument is printed. Why? This is because the remaining arguments are evaluated by the function and then ignored. 2. Too few parameters
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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This is what I have so far
1. Too many arguments.
#include <stdio.h>
Void simple();
Int main()
{
Int n;
simple(1,2,3,4,5,6,7,8,9,10,11,12);
Return0;
}
Void simple(int n){
printf(“%d”,n);
}
What does this do?
This code prints the first argument passed to the simple function called. That is (1).
Does the extra argument break the code?
No, the extra argument does not break the code as the remaining argument are ignored by the function.
Which argument(s) gets printed?
The arguments are printed in the order they are called in the function.
Here, the argument to be passed first is 1 and that is printed.
The first argument is printed.
Why?
This is because the remaining arguments are evaluated by the function and then ignored.
2. Too few parameters
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