College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Concept explainers

Electric Charges and Fields
One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.
Question

case 3 is the first picture

O Case 4 This case is identical to Case 3 with one difference; qc = 11 µC. A.) Without doing any calculations, determine the magnitude & components of the electric force that C exerts on E. Let up & right be positive. FCE = FCE,X FCE,Y %3D B.) Without doing any calculations, determine the magnitude & components of the electric force that D exerts on E. Let up & right be positive. FDE = FDE,X FDE,Y D E C.) Determine the components, magnitude, & direction of the net electric force on E because of C & D (you will need to do calculations for this part). Fnet,x Fnet,y Fnet = direction of Fnet ° relative to the VERTICAL %3D in quadrant ( 2
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Transcribed Image Text:O Case 4 This case is identical to Case 3 with one difference; qc = 11 µC. A.) Without doing any calculations, determine the magnitude & components of the electric force that C exerts on E. Let up & right be positive. FCE = FCE,X FCE,Y %3D B.) Without doing any calculations, determine the magnitude & components of the electric force that D exerts on E. Let up & right be positive. FDE = FDE,X FDE,Y D E C.) Determine the components, magnitude, & direction of the net electric force on E because of C & D (you will need to do calculations for this part). Fnet,x Fnet,y Fnet = direction of Fnet ° relative to the VERTICAL %3D in quadrant ( 2
As shown below, particle C is located at (0 cm, 19 cm), particle D is at the origin, & particle E is at (19 cm, 0 cm). Additionally, qc = -11 µC, qp = 9 µC, & qɛ = -10 µC. A.) Determine the magnitude & components of the electric force that C exerts on E. Let up & right be positive. FCE = 1.37119e1 N FCE,X FCE,Y 9.695 N = -9.695 N B.) Determine the magnitude & components of the electric force that D exerts on E. Let up & right be positive. FDE = 22.43 N FDE,X = -22.43 N D FDE,y = ON C.) Determine the components, magnitude, & direction of the net electric force on E because of C & D. Fnet,x Fnet,y Fnet = direction of Fnet HORIZONTAL in quadrant ( 3 %3D ° relative to the %3D
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Transcribed Image Text:As shown below, particle C is located at (0 cm, 19 cm), particle D is at the origin, & particle E is at (19 cm, 0 cm). Additionally, qc = -11 µC, qp = 9 µC, & qɛ = -10 µC. A.) Determine the magnitude & components of the electric force that C exerts on E. Let up & right be positive. FCE = 1.37119e1 N FCE,X FCE,Y 9.695 N = -9.695 N B.) Determine the magnitude & components of the electric force that D exerts on E. Let up & right be positive. FDE = 22.43 N FDE,X = -22.43 N D FDE,y = ON C.) Determine the components, magnitude, & direction of the net electric force on E because of C & D. Fnet,x Fnet,y Fnet = direction of Fnet HORIZONTAL in quadrant ( 3 %3D ° relative to the %3D
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