College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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please help with questions 92 and 93 based on the information given in the first picture
A 10.0-kilogram box starts from rest at point A and
is accelerated uniformly to point B in 4.0 seconds
by the application of a constant horizontal force F.
At point B, the speed of the box is 10.0 meters per
second as it begins to move up a plane inclined at
30.° to the horizontal. [Neglect friction.]
0 m/s
10.0 kg
10.0 m/s
0 = 30.°
A
B.
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Transcribed Image Text:A 10.0-kilogram box starts from rest at point A and is accelerated uniformly to point B in 4.0 seconds by the application of a constant horizontal force F. At point B, the speed of the box is 10.0 meters per second as it begins to move up a plane inclined at 30.° to the horizontal. [Neglect friction.] 0 m/s 10.0 kg 10.0 m/s 0 = 30.° A B.
92. The box comes to rest at a vertical height of h
(point D) when 0 = 30.°. If 0 was increased
93. On the axes below, sketch a line to represent the
to 40.°, the box would come to rest at a vertical
height
(1) less than h
(2) greater than h
(3) equal to h
93. On the axes below, sketch a line to represent the
relationship between the kinetic energy of the
box and its speed as it travels from point A to
point B.
A
Speed
Kinetic energy
expand button
Transcribed Image Text:92. The box comes to rest at a vertical height of h (point D) when 0 = 30.°. If 0 was increased 93. On the axes below, sketch a line to represent the to 40.°, the box would come to rest at a vertical height (1) less than h (2) greater than h (3) equal to h 93. On the axes below, sketch a line to represent the relationship between the kinetic energy of the box and its speed as it travels from point A to point B. A Speed Kinetic energy
Expert Solution
Check Mark
Step 1

Given:
m=10 kgvA=0 m/svB=10m/stAB=4.0 sθ=30°

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