The voltage drop across a parallel portion of a series-parallel circuit can be found by multiplying the total branch current by the, of the parallel branch. largest resistance smallest resistance sum of the resistances equivalent resistance For the circuit shown, the voltage drop across resistor R1 would be: IT R2= 220 12 13 R = 14 R3= 100 R4= 402 30 V 4.5V. 6V. 5V 30V. wt

Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter7: Parallel Circuits
Section: Chapter Questions
Problem 3PP: Using the rules for parallel circuits and Ohmslaw, solve for the missing values....
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The voltage drop across a parallel portion of a series-parallel circuit can be found
of the parallel branch.
by multiplying the total branch current by the
largest resistance
smallest resistance
sum of the resistances
equivalent resistance
For the circuit shown, the voltage drop across resistor R1 would be:
IT
R2= 222 12
13
14
R1 =
R3=
102
R4=
402
30 V
4.5V.
6V.
5V
30V.
Transcribed Image Text:The voltage drop across a parallel portion of a series-parallel circuit can be found of the parallel branch. by multiplying the total branch current by the largest resistance smallest resistance sum of the resistances equivalent resistance For the circuit shown, the voltage drop across resistor R1 would be: IT R2= 222 12 13 14 R1 = R3= 102 R4= 402 30 V 4.5V. 6V. 5V 30V.
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