The vector potential in free space is given as A⃗ =z^20ρ2z. In that case a) Which of the following is the correct magnetic flux density B⃗? b) Which of the following is the correct current density J⃗?
The vector potential in free space is given as A⃗ =z^20ρ2z. In that case a) Which of the following is the correct magnetic flux density B⃗? b) Which of the following is the correct current density J⃗?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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The vector potential in free space is given as A⃗ =z^20ρ2z. In that case
a) Which of the following is the correct magnetic flux density B⃗?
b) Which of the following is the correct current density J⃗?
![Serbest uzayda vektör potansiyeli A = 20p²z olarak veriliyor. O halde
a) B manyetik akı yoğunuğu aşağıdakilerden hangisinde doğru olarak verilmiştir?
a. Hiçbiri
b. -p20pz
Oc. -680p?z
O d. 620pz
e. -p20pz?
O f. -640pz
g. -220poz
O h. -p20pz3
b) J akım yoğunluğu aşağıdakilerden hangisinde doğru olarak verilmiştir?
O a. j = +[- p40p – 280z]|
O b. J
1|- 640p + 280z]
%3D
O. J = + (620øz + 280z]
- 6200z + 280z]
O d. j
(- ô40p + 280z]
%3D
O e. J = +[- p40p²z+ 280z]
O f. j
A(- ô120p + 6800 + 280z]
g. Hiçbiri
O h. j = 1– ô120pz + 080ø + 280z²]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd00b6bdf-d77b-425d-8201-7ff8ff1b0177%2Fa58049fb-39ed-4d49-b06b-bd91b30f046a%2Fpp972tlj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Serbest uzayda vektör potansiyeli A = 20p²z olarak veriliyor. O halde
a) B manyetik akı yoğunuğu aşağıdakilerden hangisinde doğru olarak verilmiştir?
a. Hiçbiri
b. -p20pz
Oc. -680p?z
O d. 620pz
e. -p20pz?
O f. -640pz
g. -220poz
O h. -p20pz3
b) J akım yoğunluğu aşağıdakilerden hangisinde doğru olarak verilmiştir?
O a. j = +[- p40p – 280z]|
O b. J
1|- 640p + 280z]
%3D
O. J = + (620øz + 280z]
- 6200z + 280z]
O d. j
(- ô40p + 280z]
%3D
O e. J = +[- p40p²z+ 280z]
O f. j
A(- ô120p + 6800 + 280z]
g. Hiçbiri
O h. j = 1– ô120pz + 080ø + 280z²]
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