The variable resistor (RL) in the circuit is adjusted for maximum power transfer to RL.a) Find the numerical value of RL.b) Calculate the power for the dependent current source and determine if itabsorbs or supplies power.c) Find the maximum power transferred to RL. 1. The variable resistor (RL) in the circuit is adjusted for maximum powertransfer to RL.a) Find the numerical value of R.b) Calculate the power for the dependent current source and determine if itabsorbs or supplies power.b) Find the maximum power transferred to R.30 Ω45 N60 Ω3.6 kVis3300 N"RL150ig30 Ω15 Ω

a) By nodal analysis V1-V230+V1-145+V130=0

The variable resistor (RL) in the circuit is adjusted for maximum power transfer to RL. a) Find the numerical value of RL. b) Calculate the power for the dependent current source and determine if it absorbs or supplies power. c) Find the maximum power transferred to RL.

The variable resistor (RL) in the circuit is adjusted for maximum power transfer to RL. a) Find the numerical value of RL. b) Calculate the power for the dependent current source and determine if it absorbs or supplies power. c) Find the maximum power transferred to RL.

Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)

10th Edition

ISBN:9781337399128

Author:Russell E. Smith

Publisher:Russell E. Smith

Chapter3: Electric Circuits

Section: Chapter Questions

Problem 11RQ

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Concept explainers

Current Division Method

The generalized current divider formula is given by the following relation below,

Question

The variable resistor (RL) in the circuit is adjusted for maximum power transfer to RL.
a) Find the numerical value of RL.
b) Calculate the power for the dependent current source and determine if it

absorbs or supplies power.
c) Find the maximum power transferred to RL.

1. The variable resistor (RL) in the circuit is adjusted for maximum power
transfer to RL.
a) Find the numerical value of R.
b) Calculate the power for the dependent current source and determine if it
absorbs or supplies power.
b) Find the maximum power transferred to R.
30 Ω
45 N
60 Ω
3.6 kV
is
3300 N
"RL
150ig
30 Ω
15 Ω

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