Delmar's Standard Textbook Of Electricity
7th Edition
ISBN: 9781337900348
Author: Stephen L. Herman
Publisher: Cengage Learning
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- A ring of ferromagnetic material has a rectangular section. The inner diameter is 15 cm.The outer diameter is 24 cm. And the thickness is 5 cm. There is a coil of 500 turns wound onthe ring. When the coil has a current of 10 A, the flux in the core is 0.0007 Wb. Theaverage length of the ring is Ln=0.66m Determine:a) The magnetomotive force.b) The intensity of the magnetic field and the flux density.c) Reluctance, permeability and relative permeability.arrow_forwardInduced voltage acts like a resistance to hinder the flow of current through an inductor. True or False It is often more desieable to the conductor instead of the magnetic field. True or Falsearrow_forwardThe permeability of a low-carbon steel is μ=2x10-4 Wb/At.m The shape of this material is a torus (looks like a doughnut), with an inner radius ri=1.75 cm and outer radius ro=2.25 cm. Calculate its reluctance. A. 11.9 x10-4 At/Wb. B. 21.9 x10-4 At/Wb. C. 31.9 x10-4 At/Wb. D. 41.9 x10-4 At/Wbarrow_forward
- A DC current I flows in a long solenoidwith n coil-turns per unit length. Thecore is made of iron with permeability µ , and has a cross section area S.Determine the force acting on the coreif it is withdrawn to the position shownin figure.arrow_forward> Figure 1 shows a ferromagnetic core whose mean path length is 40 cm. There is a small gap of 0.05 cm in the structure of the otherwise whole core. The cross-sectional area of the core is 12cm?, the relative permeability of the core is 4000 and the coil of wire on the core has 400 turns. Assume that fringing in the air gap increases the effective cross-sectional area of the air gap by 5 percent. Given this information. Find the total reluctance of the flux path (iron plus air gap) and the current required to produce a flux density of 0.5 T in the air gap. N=400 0.05 cm A-12 cm - 40 cm Figure 1arrow_forwardAdding a core of magnetic material to an electromagnet: Select one: allows greater current to flow. decreases AC impedance. greatly increases the inductance. eliminates the magnetic poles.arrow_forward
- A 420 V, four-pole, 25 kW DC generator has a wave-connected armature winding with 846 conductors. The mean flux density in the air-gap under the interpoles is 0.5 Wb/m2 on full load and the radial gap length is 0.4 cm. Calculate the number of turns required on each interpole.arrow_forwardWhat are interpoles, and what is their purpose?arrow_forwardAn ac resistance is higher than a dc resistance. True Falsearrow_forward
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