The undergraduate grade point averages (UGPA) of students taking an admissions test in a recent year can be approximated by a normal distribution, as shown in the figure. (a) What is the minimum UGPA that would still place a student in the top 15% of UGPAS? (b) Between what two values does the middle 50% of the UGPAS lie? C (a) The minimum UGPA that would still place a student in the top 15% of UGPAs is (Round to two decimal places as needed.) on the low end and on the high end. (b) The middle 50% of UGPAs lies between (Round to two decimal places as needed.) 3.42 N o 0.17 3.42 Grade point average Time Remaining: 00:34:06 Subm # 2.84

A survey was conducted two years ago asking college students their top motivations for using a credit card. To determine whether this distribution has changed, you randomly select 425 college students and ask each one what the top motivation is for using a credit card. Can you conclude that there has been a change in the claimed or expected distribution? Use a=0.10. Complete parts (a) through (d). New Survey Frequency, f 111 97 Response Old Survey % Rewards 29% 23% Low rates Cash back Discounts Other 22% 108 8% 46 18% 63 UD. XX O D. X Xo 2 OC. X >Xo OC. X>x (c) Calculate the test statistic. (Round to three decimal places as needed.) %3D (d) Decide whether to reject or fail to reject the null hypothesis. Then interpret the decision in the context of the original claim. V the claimed or ▼enough evidence to conclude that the distribution of motivations Ho At the 10% significance level, there expected distribution.

(a) Approximate the mean and standard deviation.  Round each to two decimals. (b) Complete the last two columns in the table above for relative frequency and cumulative frequency.  Round any decimals to 3 places.  Do not include the zero before the decimal.  For example for 0.56, enter .56 (c)  What is the shape of the distribution?

The number of peanuts in a 16 ounce can of nut munchies is normally distributed with a mean of 93.6 and a standard deviation of 4.2 peanuts the number of peanuts in a 20 ounce can of gone nuts is normally distributed with a mean of 111.8 and a standard deviation of 3.4 peanuts. (a) Carmen purchased a 16 ounce can of nut munchies and counted 100 peanuts what is the Z score for this can of peanuts? (b) Angelo purchased a 20 ounce can of gone nuts and counted 116 peanuts what is the Z score for this can of peanuts? (c) Carmen declares that purchase purchasing her can of nut munchies with 100 peanuts is less likely than Angelo purchasing a can of gone nuts with 116 peanuts is Carmen statement correct? Use the definition of a Z score to support or refute Carmen's claim.

scores on a statistics final in a large class were normally distributed with a mean of 76 and a standard deviation of 11 Round the answers to at least two decimals. (a) Find the 25thpercentile of the scores. (b) Find the 63rd percentile of the scores. (c) The instructor wants to give an A to the students whose scores were in the top 11%of the class. What is the minimum score needed to get an A?

z Scores LeBron James, one of the most successful basketball players of all time, has a height of 6 feet 8 inches, or 203 cm. Based on statistics from Data Set 1 “Body Data” in Appendix B, his height converts to the z score of 4.07. How many standard deviations is his height above the mean?

← The undergraduate grade point averages (UGPA) of students taking an admissions test in a recent year can be approximated by a normal distribution, as shown in the figure (a) What is the minimum UGPA that would still place a student in the top 15% of UGPAS? (b) Between what two values does the middle 50% of the UGPAs lie? GED 28 (a) The minimum UGPA that would still place a student in the top 15% of UGPAS is (Round to two decimal places as needed) p+3.40 00.16 3.40 Grade point average So L