The test statistic of z = 2.34 is obtained when testing the claim that p # 0.879.a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed.b. Find the P-value.c. Using a significance level of a = 0.05, should we reject Ho or should we fail to reject Ho?Click here to view page 1 of the standard normal distribution table.Click here to view page 2 of the standard normal distribution table.a. This is atest.(Round to three decimal places as needed.)b. P-value =c. Choose the correct conclusion below.Fail to reject Ho. There is not sufficient evidence to support the claim that p+ 0.879.A.Fail to reject Ho. There is sufficient evidence to support the claim that p +0.879.B.C. Reject Ho. There is sufficient evidence to support the claim that p + 0.879.D. Reject Ho. There is not sufficient evidence to support the claim that p#0.879.

From the given information,Test statistic of Z- value:Z = 2.34,Null and alternate hypotheses are:H0:…

Answered: The test statistic of z = 2.34 is…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The test statistic of z = 1.68 is obtained when testing the claim that p 0.302. a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. b. Find the P-value. c. Using a significance level of a = 0.01, should we reject Ho or should we fail to reject Ho? Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. a. This is a test.
Is memory ability before a meal the same as after a meal? Ten people were given memory tests before their meal and then again after their meal. The data is shown below. A higher score indicates a better memory ability. Ho: Select an answer H₁: Select an answer ✓ Before a Meal After a Meal Assume a Normal distribution. What can be concluded at the the a = 0.01 level of significance? For this study, we should use Select an answer a. The null and alternative hypotheses would be: b. The test statistic ? ✓ = Score on the Memory Test 67 44 71 77 63 76 53 50 71 82 76 54 71 86 75 88 58 49 89 83 Select an answer Select an answer V c. The p-value d. The p-value is ? ✓ a e. Based on this, we should f. Thus, the final conclusion is that ... Select an answer Select an answer (please enter a decimal) (Please enter a decimal) (please show your answer to 3 decimal places.) (Please show your answer to 4 decimal places.) Select an answer the null hypothesis.
Given in the table are the BMI statistics for random samples of men and women. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. a. Test the claim that males and females have the same mean body mass index (BMI). What are the null and alternative hypotheses? OA. Ho: H=H H₁: Hy > H₂ ỌC. Ho: H=H2 H₁: H₁ H₂ The test statistic, t, is. (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) State the conclusion for the test. -C OB. Ho: ₁2/₂ H₁ H₁ H₂ OD. Ho. Hy#t H₁: H₁ H₂ O A. Fail to reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that men and women have the same mean BMI. O B. Fail to reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that men and women…
Complete parts (a) and (b) below. Click here to view Page 1 of the table of areas under the standard normal curve. Click here to view Page 2 of the table of areas under the standard normal curve. a. The test statistic in a right-tailed test is z= 1.71. Determine the P-value and decide whether, at the 5% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. The P-value is (Round to three decimal places as needed.) This P-value V sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis because it is V the significance level. b. The test statistic in a right-tailed test is z= - 0.82. Determine the P-value and decide whether, at the 5% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. The P-value is (Round to three decimal places as needed.) This P-value sufficient evidence to reject the null hypothesis in…
A two-sided hypothesis test is being conducted for testing the mean of a normal distribution at the 90% level. The hypothesized mean value is 60 whereas the true mean is 61 with the variance being equal for both the hypothesized and real distributions at the value of 12.20. The sample size is 9. What are the values of the following in the asked order: Pr(Failing to reject the null hypothesis when it is false), Pr(Rejecting the null hypothesis when it is true), the power of the hypothesis test?
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The mean income per person in the United States is $36,000, and the distribution of incomes follows a normal distribution. A random sample of 9 residents of Wilmington, Delaware, had a mean of $46,000 with a standard deviation of $8,400. At the 0.100 level of significance, is that enough evidence to conclude that residents of Wilmington, Delaware, have more income than the national average?a. State the null hypothesis and the alternate hypothesis. b. State the decision rule for 0.100 significance level. (Round your answer to 3 decimal places.) c. Compute the value of the test statistic. (Round your answer to 2 decimal places.) d. Is there enough evidence to substantiate that residents of Wilmington, Delaware, have more income than the national average at the 0.100 significance level?
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Areas under the Normal Curve .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 0.5040 0.5438 0.5832 0.5199 0.5596 0.5239 0,5636 0.6026 0.5279 0,5675 0.6064 0.0 0.5000 0.5080 0.5120 0.5319 0.5714 0.6103 0.5160 0.5359 0.0 0.5753 0.1 0.2 0.5398 0.5478 0.5517 0.5557 0.1 0.5793 0.5871 0.5910 0.5948 0.5987 0.6141 0.2 0.6331 0.6700 0.6368 0.6480 0.6517 0.6879 0.6179 0.6217 0.6255 0.6628 0.6293 0.6664 0.6406 0.6443 0.6808 0.3 0.4 0.3 0.4 0.6554 0.6591 0.6736 0.6772 0.6844 0.6985 0.7324 0.7642 0.7224 0.7549 0.7852 0.5 0.6915 0.6950 0.7019 0.7054 0.7088 0.7123 0.7157 0.7190 0.5 0.6 0.7257 0.7291 0.7357 0.7389 0.7422 0.7734 0.7454 0.7486 0.7794 0.8078 0.7517 0.7823 0.6 0.7 0.7580 0.7611 0.7673 0.7704 0.7764 0.7 0.7995 0.8264 0.7939 0.8 0.9 0.8051 0.8315 0.8133 0.8389 0.7881 0.7910 0.7967 0.8023 0.8106 0.8 0.8159 0.8186 0.8212 0.8238 0.8289 0.8340 0.8365 0.9 1.0 0.8413 0.8485 0.8554 0.8770 0.8962 0.8599 0.8810 0.8438 0.8461 0.8508 0.8531 0.8577 0.8621 1.0 1.1 0.8643 0.8665 0.8686 0.8708 0.8830 0.8729 0.8925…
The test statistic of z = 1.50 is obtained when testing the claim that p # 0.211. a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. b. Find the P-value. c. Using a significance level of a= 0.10, should we reject Ho or should we fail to reject Ho? Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. a. This is a test. b. P-value = (Round to three decimal places as needed.) c. Choose the correct conclusion below. O A. Reject Ho. There is sufficient evidence to support the claim that p#0.211. O B. Fail to reject Ho. There is not sufficient evidence to support the claim that p#0.211. O C. Fail to reject Ho. There is sufficient evidence to support the claim that p#0.211. O D. Reject Ho. There is not sufficient evidence to support the claim that p#0.211. MacBo 000 esc 000 F4 F1 F2 F3 F5

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