The table t value associated with the upper 5% of the t distribution and 12 degrees of freedom is 1.782 3.330 1.356 2.179
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- Q2/Determine all Currents and voltages in the circuit of the figure shown, using MESH analysis. 4A 100% 12 m 200 gv 2001 1002An integer is chosen at random from the first 100 positive integers. Find the probability that the chosen integer is Multiple of 10: (a) 99/100 (b) 0 (c) 10 (d) 1/10i. Derive the linear and quatratic approximation of the below resistance temperature readings(temperature from 40 °c to 80 °c). (. ii. find out the resistance of RTD at a temperature of 200°c using linear approximation? ( Temperature 40 45 50 55 60[TO] 65 70 75 80 Resistance ohm 115.239 120.521 167.096 254.966 384.13 554.587 766.34 1019.38 1313.724
- 100 80 60 40 20 0.002 0.004 0.006 0.008 0.01 0.012 Strain, in/in. FIGURE P1.17 1.18 Use Problem 1.17 to graphically determine the following: a. Modulus of resilience b. Toughness Hint: The toughness (u) can be determined by calculating the area under the stress-strain curve u = de where & is the strain at fracture. The preceding integral can be approxi- mated numerically by using a trapezoidal integration technique: u, = Eu, = o, + o e, - 6) %3D c. If the specimen is loaded to 40 ksi only and the lateral strain was found to be -0.00057 in./in., what is Poisson's ratio of this metal? d. If the specimen is loaded to 70 ksi only and then unloaded, what is the permanent strain? Stress, ksiQ7// State the Cowper-Symonds empirical equation which describes the effect of strain rate on the flow stress of metallic materials. Using the Cowper-Symonds equation, together with the material constants D and q in the equation as given in the Table below, describe the comparative high strain rate sensitivity of the different materials (assume e° = 3 4 s'). Material D (s') Copper 4.8 52 Stainless Steel 9.2 99 Titanium Alloy 9.2 122 Aluminium Alloy 4.2 6710 Mild Steel 5.1 45Give True or False for the following: 1.In liquids and gases, heat transmission is caused by conduction and convection 2.The surface geometry is the important factor in convection heat transfer 3. The heat transfer by conduction from heated surface to the adjacent layer of fluid, 4. The heat transfer is increased in the fin when &> 1 5.The unit of the thermal diffusivity is m²/s 6. Temperature change between the materials interfaces is attributed to the thermal contact resistance 7. A material that has a low heat capacity will have a large thermal diffusivity. 8. Heat conduction flowing from one side to other depends directly on thickness 9.Fin efficiency is the ratio of the fin heat dissipation with that of no fin 10.The critical radius is represented the ratio of the convicted heat transfer to the thermal conductivity
- Q6 - The fatigue behavior of muscle under alternating stress conditions with zero mean is given by the expression o. Nf cyclic stress, N is the number of cycles to failure and C and a are material constants. Complete the data of the table below. = C, where ơr is the range of %3D O Кра Nr x 103 40 30 25 ? 1 20 5002 0 2 5 7 11 f(x) 13 5 17 28 41 Selected values of a differentiable function f are given in the table above. What is the feweWhich of the following is the unit for electrical conductivity? Select one: O (Q-m) -1 O (Q-mm) O m/S O Q-m In a stress strain curve of mild steel, the elastic limit will be before the limit of propor ype here to search 99+ hp fs 米 f5 f6 f7 1- f8 fg & 7 V 3 6. 8. 9/6 4+ %24 %23
- σ (ksi) 105 90 75 60 45 30 15 0 8 0 0 0.20 0.25 0.30 0.35 0.05 0.10 0.15 0.001 0.002 0.003 0.004 0.005 0.006 0.007 € (in./in.) The stress-strain diagram from tensile test data for a metal alloy is shown. If the diameter of testing sample is 0.5 in determine: a) UTS b) Yield Strength c) Braking/ Failure Strength d) Young Module of Elasticity e) The load causing yielding in materialTo determine the thermal conductivity of a structural material, a large 15-cm-thick slab of the material is subjected to a uniform heat flux of 2500 W/m2 while thermocouples embedded in the wall at 2.5 cm. intervals are read over a period of time. After the system had reached equilibrium, an operator recorded the thermocouple readings shown below for two different environmental conditions: Distance from the Surface (cm) Temperature (C) Test 1 0 40 5 65 10 97 15 132 Test 2 0 95 5 130 10 168 15 208 From these data, determine an approximate expression for the thermal conductivity as a function of temperature between 40 and 208C.Areas Under the Standard Normal Curve-The Values Were Generated Using the Standard Normal Distribution Function of Excel Note that the standard normal curve is symmetrical about the mean. z 0 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.1 0.11 0.12 1 0.95 0.96 0.97 0.98 0.99 1.01 1.02 1.03 1.04 1.05 Mean - 0 1.06 1.07 1.08 1.09 A 0.0000 0.0040 0.0080 0.0120 0.0160 0.0199 0.0239 0.0279 0.0319 0.0359 0.0398 0.0438 0.0478 A 0.3186 0.3212 0.3238 0.3264 0.3289 0.3315 0.3340 0.3365 0.3389 Z 0.3413 0.3438 0.3461 0.3485 0.3508 0.3531 0.3554 0.3577 0.3599 0.3621 0.13 0.14 0.15 0.16 0.17 0.18 0.19 0.2 0.21 0.22 0.23 0.24 0.25 1.12 1.13 1.14 1.15 1.16 1.17 A z 0.0517 0.0557 0.26 0.27 0.28 0.29 0.0596 0.0636 0.0675 0.3 0.0714 0.31 0.0753 0.32 0.0793 0.33 0.0832 0.34 0.0871 0.35 0.0910 0.0948 0.0987 1.18 1.19 1.2 1.21 1.22 1.23 1.24 1.25 1.26 1.27 1.28 A 0.3643 0.3665 0.3686 0.3708 0.3729 0.3749 0.3770 0.3790 0.3810 0.36 0.3830 0.3849 0.3869 0.3888 0.3907 0.3925 0.3944 0.3962 0.3980 0.3997 0.37…