The specific gravity of gasoline is approximately 0.70.(a) Estimate the mass (kg) of 50.0 liters of gasoline.(b) The mass flow rate of gasoline exiting a refinery tank is 1150 kg/min. Estimate the volumetric flow rate in liters/s.(c) Estimate the average mass flow rate lbm/min delivered by a gasoline pump.(d) Gasoline and kerosene specific gravity  0:82 are blended to obtain a mixture with a specific gravity of 0.78. Calculate the volumetric ratio (volume of gasoline/volume of kerosene) of the two compounds in the mixture, assuming Vblend  Vgasoline  Vkerosene.

The gas phase reaction A↔ R is carried out in a plug flow reactor. The reaction is reversible and of first orderwith k=0.05 s−1. The reactor operates at 8.2 atm and isothermally at 227 °C. The equilibrium constant at 227°Cis 0.5. The inlet flow into reactor is 2 mol/min and PFR volume is 10 L. Calculate the exit conversion of reactant A?

Pure solid sugar is recovered from sugar cane in a process that has multiple steps. Among all the steps, three steps are considered here (see figure below). A screen is used to separate pulp (solid material) from sugar and water. In the evaporator, a portion of the water is removed. The remaining water is removed in a crystallizer, Stream 1 Screen Stream 2 6250 kg/h 6500 kg/h 7250 kg/h Stream 3 7500 kg/h Stream 4 Pure Water Vapor Evaporator Stream 5 Stream 1 contains 14 mass percent sugar, 16 mass percent pulp, and the remaining is water. All the pulp in Stream 1 goes to Stream 2. Stream 2 contains 96 mass percent pulp. Stream 3 contains no pulp, 16 mass percent sugar, and the remaining is water, and is sent to the evaporator. Stream 4 is pure water. Stream 5 contains sugar and water and is sent to the crystallizer. Pure water (Stream 6) leaves the crystallizer at a rate of 1500 kg/h and pure sugar (Stream 7) leaves the crystallizer at a rate of 1000 kg/h. The process operates at…

The rate at which a powdered chemical dissolves is jointly proportional to: amount of undissolved portion and the difference in concentration between the actual and saturated solution (Ca and Cs respectively), that is dx/dt = kx (Cs – Ca), and Ca can expressed as the ratio of the difference between the initial amount and the amount of chemical present at any time “t” to the original volume of water. Initially, 4.5 kg of the chemical is agitated with 0.3785 m3 of H2O, and after an hour the undissolved portion reduced by 40.40%. If a saturated solution contains 0.0909 kg of chemical per gallon, find the amount of this chemical which is undissolved after 2 hours, in kilograms. Round off the values along the process to 4 decimal places to avoid deviation from the correct answer in the choices. How much is the amount of chemical undissolved after two hours in kg?Whatt is the particular solution to te DE?

Since a balanced process can always be scaled, material balance calculations can be performed on the basis of any convenient set of stream amounts or flow rates and the results can afterward be scaled to any desired extent. A basis of calculation is an amount (mass or moles) or flow rate (mass or molar) of one stream or stream component in a process. The first step in balancing a process is to choose a basis of calculation; all unknown variables are then determined to be consistent with this basis. If a stream amount or flow rate is given in a problem statement, it is usually most convenient to use this quantity as a basis of calculation. If no stream amounts or flow rates are known, assume one, preferably that of a stream with a known composition. If mass fractions are known, choose a total mass or mass flow rate of that stream (e.g., 100 kg or 100 kg/h) as a basis; if mole fractions are known, choose a total number of moles or a molar flow rate. 1. What is a balanced process? How do…