The solar wind is a thin, hot gas given off by the sun. Charged particles in this gas enter the magnetic field of the earth and can experience a magnetic force. Suppose a charged particle traveling with a speed of 7.56 x 106 m/s encounters the earth's magnetic field at an altitude where the field has a magnitude of 1.48 x 10-7 T. Assuming that the particle's velocity is perpendicular to the magnetic field, find the radius of the circular path on which the particle would move if it were (a) an electron and (b) a proton.

A proton moving at 5.50 x 106 m/s through a magnetic field of magnitude 1.77 T experiences a magnetic force of magnitude 7.30 × 10-13 N. What is the angle between the proton's velocity and the field? Step 1 The magnitude of the force on a moving charge in a magnetic field is FB = qvB sin 8, and, solving for the angle, we have the following. 8 sin -1 = sin-¹ B qvB 1.60 x 10-19 c)([ x 10-13 N |× 106 m/s) (

What is the direction of the magnetic force on current 2 (by the magnetic field of current 1)? What is the magnitude of the magnetic force between currents 1 and 2, in Newtons?    I1 = 100 A, I2 = 250 A, both wires are 1.50 m long and the distance between them is 3.00 mm. Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement.

In New England, the horizontal component of the earth's magnetic field has a magnitude of 1 . 6 × 10 - 5   T . A proton is shot vertically straight down towards the ground with a speed of 2 . 1 × 10 6   m / s . What is the magnitude of the magnetic force?

A particle with mass 3×10−2 kgkg and charge +7 μCμC enters a region of space where there is a magnetic field of 1 TT that is perpendicular to the velocity of the particle. When the particle encounters the magnetic field, it experiences an acceleration of 17 m/s2m/s2 . What is the speed of the particle when it enters the magnetic-field region? Express your answer in meters per second.

An ion with a charge to mass ratio of 1.10×104 C/kg travels perpendicular to magnetic field (B=9.0×10-1 T) in a circular path (r=0.240 m) How long does it take the ion to complete one revolution?

A very long straight wire carries a current of 3.5A from left to right in the plane of this screen. An electron with a charge of −1.6×10−19C is moving from left to right at a point that is 3.5cm above the wire. Its speed is 2.5×105m/s. What is the magnitude and direction of the magnetic force that the electron experiences due to the presence of this current-carrying wire? The permeability of free space is μ0=4π×10−7T⋅m/A.

When a charged particle moves perpendicularly to the direction of a uniform magnetic field, the direction of the magnetic force is perpendicular to both the direction of the magnetic field and the direction of the velocity of the charged particle.  Accordingly, the charge begins to move in a circular path.  Since the direction of the magnetic force is toward the center of the circular path the charged particle moves along, the magnetic force is a centripetal force (recall centripetal forces from chapter 5 of the text, covered in PHY 2010).  A schematic of such motion is shown below.  The "X"s represent the magnetic field that is directed into the plane of this screen.  The direction of velocity and magnetic force lie within the plane of this screen and are at right angles to one another, as shown below.   If a charge of magnitude 4.96x10-17C, with speed 3.74x106 m/s, and mass 5.72x10-25kg moves within the magnetic field of magnitude 2.79x10-2T, what is the resulting radius of the path…

Here the charge is 3.09 x 10^-6 C, the magnetic field strength is 1.03 T and the electric field strength is 1.05 x 10^5 N/C. The charge experiences a total force of magnitude 16.00 N as it enters the region. What is its speed as it enters the region?  8.38E+06 m/s  4.93E+06 m/s  3.45E+06 m/s  5.92E+06 m/s

A magnetic field has a magnitude of 0.0011 T, and an electric field has a magnitude of 6.4 × 103 N/C. Both fields point in the same direction. A positive 1.8-μC charge moves at a speed of 4.2 × 106 m/s in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge.