3. The section of shaft shown in the figure is to be designedto approximate relative sizes of d = 0.75D and r = D/20with diameter d conforming to that of standard metricrolling-bearing bore sizes. The shaft is to be made ofSAE 2340 steel, heat-treated to obtain minimum.strengths in the shoulder area of 1226-MPa ultimatetensile strength and 1130-MPa yield strength with aBrinell hardness not less than 368. At the shoulder theshaft is subjected to a completely reversed bending moment of 70 Nm, accompanied by a steadytorsion of 45 N m. Use a design factor of 2.5 and size the shaft for an infinite life.Note: Section of a shaft containing a grinding-relief groove. Unless otherwise specified, thediameter at the root of the groove dr = d - 2r, and though the section of diameter d is ground, theroot of the groove is still a machined surface.

Given: d=0.75D r=D/20 Sut=1226MPa=175kpsiSys=1130MPa=160kpiM=70NmT=45NmN=2.5 To find: Size the…

Answered: The section of shaft shown in the…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Bearing stress 4. Please provide proper discussion and illustration also complete solution and clear solution please thank you Determine the length of a square key to be used for a 3.73 kW, 1800 rpm electric motor if the motor shaft diameter is 35 mm and the width of the key is approximately one-fourth of the shaft diameter. The allowable shearing stress on the key is 2.45 MPa
include FBD and complete solution
• For the solid shaft shown in the figure, determine the maximum shearing stress. And the twisting angle. • The modulus of Rigidity for the shaft is 40 GN/m? • Use the last THREE digits of your ID number for the missing torque T 575 L= 0.3 m d= 4 mm 0.3m L= 0.4m d= 10 mm T=
Mechanical design The maximum load in a rotating shaft is subjected to bending moment of 1 kN.m and a torque of 1 kN.m. The member is made of steel the Ultimate Tensile Strength 440 MPa, Yield Tensile Strength 370 MPa. With a safety factor of 4, kt = km = 1.5 and keyway stress consternation is presented. According to the maximum shear stress theory, the shaft diameter will be: a. 160 mm b. 74 mm C. 145 mm d. 92.5 mm e. 60 mm f. 66 mm
A solid 2.0 in. diameter shaft is used to synchronize multiple mechanisms in a manufacturing plant. The torque delivered by the shaft is 3300 Ib-in. What horsepower must be delivered to the shaft to maintain a shaft speed of 590 rpm? What is the maximum shear stress developed in the shaft? Answer: P = hp psi Save for Later Attempts: 0 of 1 used Submit Answer
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The solid steel rotating shaft in the figure is supported at B and C, and is driven by a gear, not seen, which is linked to spur gear D which has a pitch diameter of 150 mm. The drive gear force F acts at a pressure angle of 20 degrees. The shaft transmits a torque to point A of Ta-350 N.m. The properties of machined steel shaft are Sy-420 MPa and Sut-560MPa. Use a safety factor of 2.5 and determine the minimum allowable diameter in section B and C. Assume sharp felt radii at the bearing shoulders to estimate the stress concentration factors.Explain.
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• Compute the maximum shear stress and angle of twist of each type of shaft below. – Closed tube shaft – Open tube shaft • Briefly describe which type of shaft is more effective. • See the dimensions of each tube, the value of internal torque, and the shear modulus in the next page.
Please give proper and step by step solution. solid circular shaft is subjected to a bending moment of 300 kNm, a twisting moment of 125 kNm. If the yield stress of the shaft material is 350 N/mm², determine the diameter of the shaft according to the maximum shearing stress theory of failure.
Design a hallow shaft (Diameter and length) that develops 80 kN of power while rotating at a speed of 4000 rpm. The design constrains are as under: The angle of twist not to exceed 0.200 Shear stress is not to exceed 480 MN/m? The outer diameter is to be twice the inner diameter. The shaft length is to be three times the outer diameter. Modulus of rigidity = 79 GN/m?.

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