The same amount of heat entering identical masses of different substances produces different temperature changes. Calculate the final temperature when 1.70 kcal of heat enters 1.38 kg of the following, originally at 30.2°C. The specific heat capacity for each material given in square brackets below. (a) water [1.00 kcal/(kg · °C)] °C (b) concrete [0.20 kcal/(kg · °C)] °C (c) steel [0.108 kcal/(kg · °C)] °C (d) mercury [0.0333 kcal/(kg • °C)] °C

The same amount of heat entering identical masses of different substances produces different temperature changes. Calculate the final temperature when 1.70 kcal of heat enters 1.38 kg of the following, originally at 30.2°C. The specific heat capacity for each material given in square brackets below. (a) water [1.00 kcal/(kg · °C)] °C (b) concrete [0.20 kcal/(kg · °C)] °C (c) steel [0.108 kcal/(kg · °C)] °C (d) mercury [0.0333 kcal/(kg • °C)] °C

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter20: The First Law Of Thermodynamics

Section: Chapter Questions

Problem 20.7OQ: The specific heat of substance A is greater than that of substance B. Both A and B are at the same...

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