The real image of a concave mirror is six times as large as the object.  Determine the image distance (in cm) for an object that is 18.0 cm from the mirror.

A concave mirror has a radius of curvature of 35.0 cm. What is its focal length? A ladybug 7.70 mm tall is located 22.6 cm from this mirror along the principal axis. Find the location of the image of the insect. Find the height of the image of the insect.

A thin, diverging lens having a focal length of magnitude 45.0 cm has the same principal axis as a concave mirror with a radius of 60.0 cm. The center of the mirror is 20.0 cm from the lens, with the lens in front of the mirror. An object is placed 23.0 cm in front of the lens. 1)Where is the final image due to the lens–mirror combination? Enter the image distance with respect to the mirror. Follow the sign convention. (Express your answer to three significant figures.) 4)Suppose now that the concave mirror is replaced by a convex mirror of the same radius. Where is the final image due to the lens–mirror combination? Enter the image distance with respect to the mirror. Follow the sign convention. (Express your answer to three significant figures.)

A tall tree is growing across a river from you. You would like to know the distance between yourself and the tree, as well as its height, but are unable to make the measurements directly. However, by using a mirror to form an image of the tree and then measuring the image distance and the image height, you can calculate the distance to the tree as well as its height. Suppose that this mirror produces an image of the sun, and the image is located 1.0915 m from the mirror. The same mirror is then used to produce an image of the tree. The image of the tree is 1.2078 m from the mirror. (a) How far away is the tree? (b) The image height of the tree has a magnitude of 0.18 m. How tall is the tree? (a) do = (b) ho= i

A virtual image of magnification +0.5 is produced when an object is placed 10 cm in front of a curved mirror.  Determine the radius of curvature of the mirror.

An object (height = 7.7 cm) and its image are on opposite sides of a converging lens. The object is located 14.0 cm from the lens. The image is located 5.6 cm from the lens. Determine the image height (in cm). Enter the numerical part of your answer to two significant figures. Hint: Remember that the sign of the image height is significant.

A spherical mirror is polished on both sides. When the concave side is used as a mirror, the magnification is +2.6. What is the magnification when the convex side is used as a mirror, the object remaining the same distance from the mirror? If the object is inverted, then enter a negative number. Otherwise, enter a positive number. Number i Units >

The virtual image produced by a convex mirror is one fifth the size of the object. If the object is 30.9 cm in front of the mirror, what is the image distance? 10.3 cm Submit Answer Incorrect. Tries 1/5 Previous Tries What is the focal length of this mirror? Submit Answer Tries 0/5

A concave mirror produces a real image that is 3.0 times as tall as the object itself. If the object is 15.0 cm in front of the mirror: a) what is the image distance? b) what is the focal length of the mirror? Show the algebraic form of any equation(s) applied and report all answers with the correct units and number of significant figures.

Box answers for A and C, keep getting it wrong.