A thin, diverging lens having a focal length of magnitude 45.0 cm has the same principal axis as a concave mirror with a radius of 60.0 cm. The center of the mirror is 20.0 cm from the lens, with the lens in front of the mirror. An object is placed 23.0 cm in front of the lens. 1)Where is the final image due to the lens–mirror combination? Enter the image distance with respect to the mirror. Follow the sign convention. (Express your answer to three significant figures.) 4)Suppose now that the concave mirror is replaced by a convex mirror of the same radius. Where is the final image due to the lens–mirror combination? Enter the image distance with respect to the mirror. Follow the sign convention. (Express your answer to three significant figures.)

Box answers for A and C, keep getting it wrong.

You are given a spherical mirror and wish to determine its properties. You place an object on its axis, 33.5 cm in front of it, and discover that the mirror creates a virtual image located 14.5 cm from the mirror. Determine the mirror's focal length / in centimeters. Calculate the mirror's radius of curvature C in centimeters. If it can be determined, is the mirror concave or convex? convex concave cannot be determined. cm cm

In the figure below, a diverging lens and concave spherical mirror are positioned along an optical axis, with an object half way between the two. The distance between the lens and mirror is d = 23.6 cm. The magnitude of the mirror's radius of curvature is 20.1 cm, and the lens has a focal length of flens = -19.0 cm. Lens Object Mirror (a) Considering only the light that leaves the object and travels first toward the mirror, locate the final image formed by this system. (Give the magnitude of the image distance in cm, and select its location with respect to the lens.) image distance image location -Select--- (b) Is this image real or virtual? O real O virtual (c) Is it upright or inverted? O upright O inverted (d) What is the overall magnification? cm

A student notices that the image produced from a large concave mirror of a distant skyscraper of height hs= 106 m is inverted and the magnitude of the height is |hiI = 1.46 m tall. The image is located di = 178 cm in front of the mirror. A)Write an expression for the distance between the mirror and the skyscraper, ds. B) What is the distance between the mirror and the skyscraper in meters? C) What is the focal length of the mirror, f, in centimeters?

An object is 30.0 from a spherical mirror, 1 magnification is. The image produced is inverted. What is along the central axis. The absolute value of lateral 2 the focal length of the mirror?

+ Mirror Equation: Si So M; = = - Yo So Principle Ray: the ray from object to mirror that is parallel to the principle (optical) axis will reflect in a path that intersects the image focal point. Radius Ray: the ray from the object whose path is aligned curvature center point will reflect directly back to the center point on the principle (optical) axis. Central Ray: the ray from the object whose path is directed towards the center of the mirror (intersection with the principle axis) will reflect from the lens in the opposite direction with respect the optical path. Conventions: Quantity Sign Positive (+) Negative (-) Object distance So Real object Virtual object Image distance Si Real image Virtual image Focal length Concave mirror Convex mirror (opposite side of o,i) Radius of curvature R Convex Concave Object height Yo Erect object Inverted object Image height Yi Erect image Inverted image Magnification (transverse) MT Erect image Inverted image For the following mirror…

You have a concave spherical mirror (the same holds if you had a convex mirror) If the value of q(the distance from the image to the mirror along the principal axis of the mirror) is 1.45m and the distance of p (the distance from the object to the mirror along the principal axis of the mirror) is 4.11m, what is the focal length of the mirror? The magnification equation and the sign convention for q imply that real images of real objects are always inverted (if both p and q are positive, m is negative); virtual images of real objects are always upright (if p is positive and q is negative, m is positive).  Keeping the signs of p and q straight in your mind is the most challenging aspect of mirrors (and lenses).  Fortunately, table 23.2 summarizes when p and q are positive and when they are negative.

An object 1.30 cm high is held 3.00 cm from a person's cornea, and its reflected image is measured to be 0.167 cm high. What is the magnification? magnification: Where is the image? image distance: cm Find the magnitude of the radius of curvature of the convex mirror formed by the cornea. magnitude of radius of curvature: cm