The reaction of Nb (CH2CMe3)3Cl2 with two equivalents of LiCH2CMe3leads to the formation of compound F, LICI and one equivalent ofneopentane CMe4. Reaction of compound F with benzaldehyde,Ph-CHO, produces the olefin PhCH=CHCMе3 and[Nb(CH2CMe3)30]n. Give the structural formula of compound F andoutline the reaction mechanism for the formation of PhCH=CHCMe3.

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Answered: The reaction of Nb (CH2CMe3)3Cl2 with…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Compound E is a branched molecule with the molecular formula of CH140. Compound E reacted with hot concentrated phosphoric acid to form Compound F (major product). Compound G was produced when Compound F reacted with hydrogen gas in the presence of platinum while Compound H was produced when Compound F reacted with Br2 in H20. Compound F reacted with hydrogen bromide in the presences of hydrogen peroxide to form Compound I. Compound J formed when Compound F reacted with cold dilute manganate (VII) ions while Compound K formed when Compound F reacted with hot acidified concentrated potassium permanganate. Compound I was heated with aqueous sodium hydroxide to produce Compound L. Compound M was produced when Compound I reacted with aqueous ammonia in ethanol while Compound N was produced when Compound I reacted with sodium cyanide. Identify the possible structural formulae for compound E to N. State ONE test to differentiate between Compound F and Compound G. Give TWO differences between…

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