A mixture of 0.856 mol of NO, 0.656 mol of H₂, and 1.16 mol of H₂O is placed in a 1.0-L vessel at 300 K. The following equilibrium is established: 2NO(g) + 2H₂(g) = N₂(g) + 2H₂O(g) At equilibrium [NO] = 0.248 M. ▼ Part C Calculate the equilibrium concentration of H₂O. Express the molarity to three decimal places. 15. ΑΣΦ 0.608 Submit Previous Answers Request Answer Part D ESS Ne X Incorrect; Try Again; 5 attempts remaining Calculate Ke Express your answer to two significant figures. IVE ΑΣΦ Kc = 7.9.10² ? ? M

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