The reaction glyceraidehyde-3-phosphate NAD + P→ 1.3 diphosphoglycerale NADH + H has a standard reaction free energy (pH 7) of A.G 6.3 kJ mol ▼ Part A If the standard reduction potential of NAD +H+2e →NADH is 0.324 V, the reaction 1,3 dphosphoglycerate+ADP 3-phosphoglycero-ATP has a standard reaction free energy (pH 7) of A, G = -18.8 kJ/mol and the ATP hydrolysis reaction ATPH20 ADP- P₁ +H+ has a standard reaction free energy (pH 73 af-31.0 kamot, calculane the standard reduction poiantial for the reaction 3 phosphegyre+2+381 gyeraldehyde-3-phosphate + H₂0 Express your answer to three significant figures and include the appropriate units 2- PA .574 ↑ + Predoute 7

12- An electrochemical cell is composed of pure copper and pure cadmium electrodes immersed in solutions of their respective divalent ions. For a 6.5 × 102 M concentration of Cd²+, the cadmium electrode is oxidized, yielding a cell potential of 0.775 V. Calculate the concentration 2+ of Cu ions if the temperature is 25°C. Electrode Reaction Au³+ + 3e - Au O₂ + 4H+ 4e¯ Pt2+ + 2e Ag+ e Fe³+ + e O₂ + 2H₂O + 4e4(OH™) Cu H₂ Pb Cu²+ + 2e → 2H₂O Pt Ag Fe²+ 2H + 2e Pb²+ + 2e - Sn²+ + 2e -> Sn Ni²+ + 2e →→→ Ni Co²+ + 2e Co Cd²+ + 2e Cd Standard Electrode Potential, V° (V) +1.420 +1.229 ~+1.2 +0.800 +0.771 +0.401 +0.340 0.000 -0.126 -0.136 -0.250 -0.277 -0.403

An iron–sulfur protein in Complex III donates an electron to cytochrome c1. The reduction half-reactions and Ɛ°' values are shown below. Calculate the standard free energy change. Use 2 significant figures. FeS (ox) + e– → FeS (red) Ɛ°' = 0.280 V cyt c1 (Fe3+) + e– → cyt c1 (Fe2+) Ɛ°' = 0.215V

A fluoride ISE immersed in 1 x 10•2 mol dm solution of sodium fluoride gives a potential of 35,2 mV and when it is immersed in a tooth paste solution it gives a potential of 30,2 mV. What is the concentration of fluoride ion in the toothpaste?

Consider the following reductions. Cr2+(aq) + 2 e- ⟶⟶ Cr(s)                              Eored = - 0.910 V Co2+(aq) + 2 e- ⟶⟶ Co(s)                            Eored = - 0.280 V Which element is the better oxidizing agent? Explain your answer.

Use standard reduction potentials to calculate the standard free energy change in kJ for the reaction: 2H+ (aq) + Hg(1)→ H₂(g) + Hg²+ (aq) 2H+ (aq) + 2e¯ → H₂(g) Fº red 2+ Hg2 (aq) + 2e¯ → Hg(1) AGO = || kJ K for this reaction would be Eº red = 0.000 V = = 0.855 V than one.