The radioactive isotope selenium-75 is used in medical imaging as indicated on the table above. If 49.1 milligrams of selenium-75 is administered to a patient, how many milligrams are left in the body after 590.0 days? mg
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- What were the two main pursuits of alchemy? What were the contributions of alchemy to modern chemistry?Consider the accompanying diagram. Ball A is allowed to fall and strike ball B. Assume that all of ball As energy is transferred to ball B at point I, and that there is no loss of energy to other sources. What is the kinetic energy and the potential energy of ball B at point II? The potential energy is given by PE = mgz, where m is the mass in kilograms, g is the gravitational constant (9.81 m/s2), and z is the distance in meters.The radioactive isotope thallium-201 is used in medical imaging as indicated on the table above. If 55.1 milligrams of thallium-201 is administered to a patient, how many milligrams are left in the body after 12.2 days? mg
- Palladium-103 is a radioactive isotope used in prostate brachytherapy and has a half-life of 14.3 days. If 1.5 grams of palladium-103 is administered to the patient how much will remain after 28.6 days? Be sure to use correct significant figures and units in your answer.An archeologist was investigating a dig site and found charcoal in a pre-historic fire pit. Charcoal consists mostly of the element carbon. There are three naturally occurring isotopes of carbon: 12C, 13C, and 14C. Carbon-14 is radioactive and can be used to date the charcoal. The archeologist collected a sample for testing and learned that the carbon-14 activity was found to be 10 counts per minute. A sample of new charcoal of similar size showed a carbon-14 activity of 640 counts per minute. How many carbon-14 half-lives have occurred? Estimate the age of the charcoal. (The half-life of 14C is 5,730 years.)Iodine-125 is radioactive and has a half life of 60.25 days. How much of a 8.10 mg sample would be left after 58.8 days? Round your answer to 2 significant digits. Also, be sure your answer has a unit symbol. 0 x10 X μ Ś ? 000
- A brain scan uses the radioisotope oxygen-15. The recommended dosage is 50 mCi . A supply of 230 mCi in 40mL arrives at the lab.How many mL will be injected into a patient?Studying the decay of radioactive isotopes in dead organisms helps scientists to identify fossilized remains. The ratio of C-12 to C-14 in the atmosphere is 1 x 1012. The table BELOW shows this ratio inside the body of three organisms. C12/C14 Ratio Organism C12/C14 Ratio A 1 x 1012 B 2 x 1012 C 4 x 1012 What can most likely be concluded from the info above? Only Organism A is dead, and Organism C is older than Organism B. Only Organism A is dead, and Organism B is older than Organism C. Both Organism B and Organism C are dead, but Organism C has been dead longer than Organism B. Both Organism B and Organism C are dead, but Organism B has been dead longer than Organism C.Thallium-201 is a radioisotope used in brain scans. If the recommended dose is 3.0 mCimCi and a vial contains 70. mCimCi in 50. mLmL , how many milliliters should be injected?
- A brain scan uses the radioisotope oxygen-15. The recommended dosage is 50 mCi. A supply of 250 mCi in 20 mL arrives at the lab. How many milliliters will be injected into a patient?How did you get this? k===0.693t1/20.69315 hrs0.0462 hrs−1k=0.693t1/2=0.69315 hrs=0.0462 hrs 0.693 a 102.0 nanogram(ng) sample of sodium-24 was stored in a lead-lined cabinet for 2.5 days How much sodium-24 remained? The half-life os sodium -24 is 15 hours _________ ng sodium -24 remain check_circle Expert Answer thumb_up thumb_down Step 1 Radioactive decay is a first order reaction. Conversion of days into hours: 1 day2.5 days===24 hrs2.5×2460 hrs1 day=24 hrs2.5 days=2.5×24=60 hrs Calculation of k: k===0.693t1/20.69315 hrs0.0462 hrs−1k=0.693t1/2=0.69315 hrs=0.0462 hrs-1 Step 2 Radioactive decay is a first order reaction, therefore: [A]=[Ao] e−kt[A]=[Ao] e-kt where [A] is the final amount remained at time t, [Ao] is the initial amount. Putting values: [A]====102.0 ng×e−0.0462 hrs−1×60 hrs102.0 ng×e−2.772102.0 ng×0.062546.38 ng[A]=102.0 ng×e-0.0462 hrs-1×60 hrs=102.0 ng×e-2.772=102.0 ng×0.06254=6.38 ng Thus 6.38 ng of sodium-24 remained.11. At death, a nobleman in ancient Egypt was mummified and his body contained 1.4 x 103 g of potassium-40 (t1/2 = 1.25 x 10° yr), 1.2 x 108 g of carbon-14 (t1/2 = 5730 yr) and 4.8 x g of tritium (hydrogen-3) (t1/2 = 12.26 yr). Calculate the mummy's age with all three elements and then identify which element gave the most accurate estimate of the mummy's age. 10-14 100% Give Feedback to Micro TSC CROCKETT IVY