the quenching cracking that may occur when hardening some parts. Describe the alternative methods applied to prevent this situation by showing them on a single figu
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Explain the reason for the quenching cracking that may occur when hardening some parts. Describe the alternative methods applied to prevent this situation by showing them on a single figure.
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- Q1: 1.5 in diameter steel part is quenched in oil with no agitation. (H=0.20). If we use a 4340; 4140; 8640; 5140; 1040 steel, what would be the hardness number at the center of the part? Q2: Determine the best quenching medium to produce a minimum hardness of HRC 40 at the center of a 3.75 cm diameter 4320 steel bar.Consider the tensile stress strain curves in Figure 8-20 labeled 1 and 2 and answer the following questions. These curves are typical of metals. Consider each part as a separate question that has no relationship to previous parts of the question. (a) Which material has the larger work hardening exponent? How do you know? (b) Samples 1 and 2 are identical except that they were tested at different strain rates. Which sample was tested at the higher strain rate? How do you know? (c) Assume that the two stress strain curves represent successive tests of the same sample. The sample was loaded, then unloaded before necking began, and then the sample was reloaded. Which sample represents the first test: 1 or 2? Haw do you know?36 Asiacell O Homework 4 -... -> 3 Class Materials Eng. Dep. Heat Treatment Ismail Ibrahim Marhoon Homework 4 Q1: 1.5 in diameter steel part is quenched in oil with no agitation. (H=0.20). If we use a 4340; 4140; 8640; 5140; 1040 steel, what would be the hardness number at the center of the part? Q2: Determine the best quenching medium to produce a minimum hardness of HRC 40 at the center of a 3.75 cm diameter 4320 steel bar. Given Cingrate t 00c00 143 to 4340 50 40 8640 ab 9310 30 4320 1050 1040 10 20 it 1 1 2n 10 20 30 Jominy distance th of an inch) Die he eted e TABLE The N canticient, or seveity of the querch, far several guenehing sedla H Coefticient Coaling Rate at he Center of a l-in. Bar (CA) Medium Ol no taton) 04 anitation) 025 18 45 HyD inc agtation H0 fegiutont Brine Ino agtaton) Brine lapttiori 10 4.0 190 20 60 90 230 Ad DISTANCE FROM OUENCHED END IN) DIAMETER IN)
- Q1: Austenitized 40 mm diameter 5140 alloy steel bar is quenched in agitated oil. Predict what is the Rockwell hardness of this bar will be at (a) its surface and (b) its center (c) What do you think about the difference in hardness number between the center and surface (d) Differentiate between hardness and hardenability (e) Rank the steels in the figure below from lowest to highest hardenability and explain why. 600- Bar diameter (mm) 100 80 60 40 20 0 300 0 Cooling rate at 700°C (°C/sec). -150 55 0 تنا 25 ------- 5 S 10 12.5 8 M-R L 1/2 34-R Agitated oil 15 20 ¼ ¾ Distance from quenched end. De (Jominy distance) 5,5 54 Car Bar diameter (in.) 0 25 mm. 1 in. Hardness (Rockwell C) Where (C = center, S = surface, M-R = mid-radius) 2828 292 65 60- 55- 50 45 40 35 30 25 20 15 10 0 J 10 5140 30 20 Distance from quenched end (mm) 4340 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 Distance from quenched end (sixteenths of an inch) 40 9840 4140 8640 50out of (a). Briefly explain THREE (3) sources of internal residual stresses in metal components and state the consequences of these stresses. Huraikan secara ringkas TIGA (3) sumber tegasan baki dalaman di dalam komponen logam dan nyatakan akibat tegasan tersebut (b). Describe with the aid of an illustration, heat treatment procedures for steels and state the intended final microstructure. Dengan bantuan gambar rajah, huraikan tatacara rawatan boba untuk keluli yang berikut serta nyatakan mikrostruktur akhir yang dikehendaki. (). Full annealing Penyepuhlindapan penuh (i). Normalizing Penormalan (ii). Tempering PembajaanQ1: Austenitized 40 mm diameter 5140 alloy steel bar is quenched in agitated oil. Predict what is the Rockwell hardness of this bar will be at (a) its surface and (b) its center (c) What do you think about the difference in hardness number between the center and surface (d) Differentiate between hardness and hardenability (e) Rank the steels in the figure below from lowest to highest hardenability and explain why. Cooling rate at 700°C (°C/sec) 300 150 011/3 55 100 600 Bar diameter (mm) 80 60 40 20 0 OLL 0 0 ww 25 12.5 8 5 S -------------- M-R 10 3/4-R Agitated oil 15 20 1/4 3/4 Distance from quenched end. De (Jominy distance) 5.5 4 3 Bar diameter (in.) 0 25 mm 1 in. Hardness (Rockwell C) Where (C = center, S = surface, M-R mid-radius) 65 60 55 50 45 40 35 30 25 20 15 10 0 10 1 20 Distance from quenched end (mm) 5140 1 30 L 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 Distance from quenched end (sixteenths of an inch) 4340 40 9840 4140 8640 50
- The figure shows two work pieces of steel of 0.3 %C and 1.3 %C with different dimensions. compare between them regarding the diagram that shows the stages of softening annealing treatments. Subject: MetallurgyWhich of the following is a method for strengthening metals and alloys: a. solution hardening b. full annealing c. work hardening d. incomplete casting e. cold working f. quenching g. incomplete fusionPick the best soultion for the multiple choices. Modulus of resilience is: Slope of elastic portion of stress – strain curve Area under the elastic portion of the stress –strain curve Energy absorbed during fracture in a tension test Energy absorbed during fracture in an impact test Slope of the plastic portion of the stress- strain curve ( ) Fatigue failure occurs under the condition of: High elastic stress High corrosivity High stress fluctuations High temperature High rate of loading ( ) Creep failure of a material occurs most rapidly when the operating temperature is: Cryogenic temperature Equal to its melting point Grater than 0.4 times its melting point in K Greater than 200 oF Close to boiling point ( ) Young’s modulus of a material is indicative of its: Tensile strength Yield Strength Ductility Stiffness Corrosion Resistance…