The procedure calls for you to add extra NaOH based on the amount of acidic hydrogens you have on your phenol. You've already added 10 mmol of you phenolic coupling partner, and the base 10 mL for the reaction, so now you're only accounting for the extra amount based on the acidic hydrogens. Looking at the photo below, how many extra mL of 2M NaOH would you add? Consider all OH and COOH hydrogens acidic. OH
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- Why should you keep your head out of the fume hood during the reaction between tetraphylcyclopentadienone and Dimethyl acetylenedicarboxylate? Because the addition of heat to this experiment increases the pressure within the reaction vessel, the apparatus could explode unexpectedly. O Due to the formation of carbon monoxide gas, which is toxic if inhaled. Due to the formation of carbon monoxide, carbon dioxide, and ethylene gas, which are all toxic when inhaled. O All of the aboveQ2Show why the OH functional group, of phenol below, is ortho directing using curly arrows to show the formation of each of the four resonance structures A, B, C and D. Draw all the resonance structures A through D and explain why one resonance structure is more favourable than the other three in directing the electrophile (E*) ortho to the OH functional group.In the reaction series below, write down the appropriate reagents that can be used where there are question marks.
- 5. Provide an efficient synthesis for the following transformation. Synthesis with the fewest steps, best yields and best selectivity will get maximum marks. Me,SiQHelp ASAP Illustrate the resonance effect of the methoxy group -OCH3, on the structure of the benzene ring. Do this by writing all the possible resonance forms for methoxybenzene, including the hybrid. Based on your structures, explain how the presence of the -OCH3 group affects: (i) the reactivity of the benzene ring towards electrophilic attack; (ii) the orientation or point of attack of an incoming electrophilic reagent on the benzene ring.In the presence of excess base and excess halogen, a methyl ketone is converted to a carboxylate ion. The reaction is known as the haloform reaction because one of the products is haloform (chloroform, bromoform, or iodoform). Before spectroscopy became a routine analytical tool, the haloform reaction served as a test for methyl ketones: the formation of iodoform, a bright yellow compound, signaled that a methyl ketone was present. Why do only methyl ketones form a haloform?
- In the following reaction Series, write down the appropriate reagents that can be used where there are question marksIn each reaction box, place the best reagent and conditions from the list. 1) CEN 2) 3) 4) 5) Answer Bank NANH, NaBH, acetone CH,CH, MgBr (excess) acetic acid acetate ion CH,OH, H,O* (cat.) LIAIH, (CH,),CHMgBr (excess) CH,MgBr (excess) H,0 H,0*, H,0, heat acetyl chloridePlease help, I need a tutor with organic chemistry background. In the picture are the 1H NMR and 13C NMR spectra for a ketone and the resulting product from the reduction reaction with sodium borohydride. draw out the structure for ketone given the name. Draw the structure of the major reduction product and provide its systematic IUPAC name. Then identify which proton(s) or carbon atom(s) is giving rise to each of the signals or groups of signals as indicated. Compare and contrast the reactant and product 1H NMR and 13C NMR to explain how they together confirm product formation based on the signals you have assigned
- This question has multiple parts. Work all the parts to get the most points. a The following compound was synthesized from the reaction of an acetylide ion with a carbonyl compound (i.e. an aldehyde or a ketone), followed by a reduction. OH CH3CH2CH2CCH=CH2 ČH»CH2CH3 Draw the structure of both the aldehyde/ketone and the acetylide ion that were used. • You do not have to consider stereochemistry. • Do not include cationic counter-ions, e.g., Na", in your answer. Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. • Separate structures with + signs from the drop-down menu. PreviousDraw a flowchart showcasing the purification step done for the reaction under basic conditions (the basic reaction of 4-methoxyacetophenone with bleach, sodium hydroxide, and acetone), starting from the crude reaction mixture all the way to the isolated solid product. Assume for this drawing that the reaction was complete, and that none of the intermediates are found in the crude mixture. There may still be however traces of your starting material in the crude mixture, along with any excess reagents2. Show the organic product formed when methyl propanoate is reacted with lithium diisopropyl amide, then methyl ethanoate is slowly added to the mixture. The mixture is neutralized with aqueous acid to obtain a neutral product. (A) Show the steps in the mechanism as reactant is converted to final product. show appropriate arrow pushing and any charges. (B) Draw a box around the final product.