The probability that a rose bud blooms is p. In a random sample of 500 rose buds, 240 of them bloomed. With the data obtained in a random sample, a hypothesis test at the 1% level of significance is carried out to determine whether p is different from 0.45. a) State the null and alternative hypothesis b) Calculate the test Statistics c) What is the p-value of the test? d) Supporting your answer, state the conclusion of the test

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Question 2
The probability that a rose bud blooms is p. In a random sample of 500 rose buds, 240 of them
bloomed.
With the data obtained in a random sample, a hypothesis test at the 1% level of significance is
carried out to determine whether p is different from 0.45.
a) State the null and alternative hypothesis
b) Calculate the test Statistics
c) What is the p-value of the test?
d) Supporting your answer, state the conclusion of the test
Transcribed Image Text:Question 2 The probability that a rose bud blooms is p. In a random sample of 500 rose buds, 240 of them bloomed. With the data obtained in a random sample, a hypothesis test at the 1% level of significance is carried out to determine whether p is different from 0.45. a) State the null and alternative hypothesis b) Calculate the test Statistics c) What is the p-value of the test? d) Supporting your answer, state the conclusion of the test
Probability
Poisson distribution
P(A or B) = P(A) + P(B) – P(A and B)
P(A and B) = P(A) x P(B) for independent events
X- Po(A)
P(A and B) = P(A) x P(B|A) for dependent events
P(X - x) = **
x!
P(A and B)
P(B|A) =
P(A)
Confidence Interval
Normal Distribution
1. z-confidence
interval:
X- N(4, ơ)
X-u
2. t-confidence
interval:
1. Standard normal: Z -
(df -n-1)
3. Confidence interval
for proportion:
P(1 – P)
n
Sampling Distribution
1. 4 =4
2.
Test Statistics
X-4
1. z-test for p : 2=
3.
X - µ
2.
t-test for u: t =
(d.f. = n-1)
S/ Vn
Discrete Probability Distribution
3. z-test forp: z-
» np 2 5
1. EÇX) = µ, = Ex,P,
P(1 - P),
and np z 5 (where q = 1-p)
Var(X) = o = 2(x, -4,)°p,
%3D
%3D
4. Chi-square test statistic = y0- E)
(0-E)
Binomial Distribution
Σ
X- Bin(n, p)
n-k
P(X - k) -
P" (1-
n!
p (1-
n-k
k!(n -k)!
Transcribed Image Text:Probability Poisson distribution P(A or B) = P(A) + P(B) – P(A and B) P(A and B) = P(A) x P(B) for independent events X- Po(A) P(A and B) = P(A) x P(B|A) for dependent events P(X - x) = ** x! P(A and B) P(B|A) = P(A) Confidence Interval Normal Distribution 1. z-confidence interval: X- N(4, ơ) X-u 2. t-confidence interval: 1. Standard normal: Z - (df -n-1) 3. Confidence interval for proportion: P(1 – P) n Sampling Distribution 1. 4 =4 2. Test Statistics X-4 1. z-test for p : 2= 3. X - µ 2. t-test for u: t = (d.f. = n-1) S/ Vn Discrete Probability Distribution 3. z-test forp: z- » np 2 5 1. EÇX) = µ, = Ex,P, P(1 - P), and np z 5 (where q = 1-p) Var(X) = o = 2(x, -4,)°p, %3D %3D 4. Chi-square test statistic = y0- E) (0-E) Binomial Distribution Σ X- Bin(n, p) n-k P(X - k) - P" (1- n! p (1- n-k k!(n -k)!
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