The pressure of the natural gas installation is as follows. As you can see, mercury (mercury), oil (oil) and water (water) fluids It is measured with a manometer. Open end of the manometer (X + 85) It is under the influence of kPa ambient pressure. The relative content of mercury and oil (relative to water) density (SG) and density of water (ρwater = 997 kg / m3 ) is known. Determine the absolute pressure in the installation (X=00)

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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The pressure of the natural gas installation is as follows.
As you can see, mercury (mercury), oil (oil) and water (water) fluids
It is measured with a manometer. Open end of the manometer (X + 85)
It is under the influence of kPa ambient pressure. The relative content of mercury and oil (relative to water)
density (SG) and density of water (ρwater = 997 kg / m3
) is known.
Determine the absolute pressure in the installation (X=00)

Oil
SG=0,69
2 cm
Natural
Gas
10 cm
25 cm
6 cm
`Mercury
SG= 13.6
Water
Transcribed Image Text:Oil SG=0,69 2 cm Natural Gas 10 cm 25 cm 6 cm `Mercury SG= 13.6 Water
Expert Solution
Step 1

Let PNG(A) be the absolute pressure of natural gas in the installation.

Given fluid in the manometer: For mercury: density, ρm=13.6×997 kg/m3=13559.2 kg/m3;

For oil of specific gravity = 0.69;ρo=0.69×997 kg/m3=687.93  kg/m3

For water, ρw=997 kg/m3  

 

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