The presence of the polar hydroxyl groups makes carbohydratessoluble in water. True or false? Explain?
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A:
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The presence of the polar hydroxyl groups makes carbohydrates
soluble in water. True or false? Explain?
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- CH₂OH C=0 но-с-н H-C1OH H-C1OH H-C1OH CH₂OH Which of the following statements correctly describes the above carbohydrate? A) This monosaccharide is fructose. B This monosaccharide is the D-isomer of ketoheptose. This monosaccharide is galactose. This monosaccharide is the L-isomer of ketoheptose.Lipids serve as all of the following exceptAlthough the first two carbons of fructose and glucose are identical in structure to DHAP and GADP (from glycolysis), DHAP and GADP equilibriate on their in solution to favor the ketone over the aldehyde, while fructose and glucose do not. Why? a)The larger size of the molecule sterically hinders the isomerization b)The larger sugars have more OH groups which hydrogen bond and disrupt isomerization c)The larger sugars cyclize, and there is no carbonyl to isomerize in the cyclic form d)The larger sugars cyclize, and in the cyclic form the hydrogen bonding is very strong e)The larger sugars are less soluble in water than the smaller sugars
- The molecule glutaraldehyde is properly described as : a five carbon chain with a ketone group on each end a five carbon chain with a ketone functional group in the middle a five carbon chain with an aldehyde group on each end a six carbon chain with and aldehyde group on each endRefer to the figure below. Determine whether the given descriptions between the relationship of glucose and galactose is correct or incorrect. * сно ÇHO H OH HO-H H- -OH HO-H HO H- H-OH ČH,OH D-Glucose -H -OH H- -он CH,OH D-Galactose CORRECT INCORRECT Glucose and galactose are both Aldohexoses They constitute the structure of the disaccharide maltose They are epimers at carbon 4 They are not mirror images of each other, neither an enantiomeric pairFor a sugar to behave as a reducing sugar, it must have a free aldehyde group. Fructose is a ketose, yet it behaves like a reducing sugar. Explain.
- Identify the component monosaccharides of each of the following compounds and describe the type of glycosidic linkage in each.Write the reaction equation for the formation of sucrose, indicate the bonds that connect the monosaccharides in the disaccharide. Biological value of sucrose.Which of the following are a pair of structural isomers? Glucose and Mannose Galactose and Fructose Ribulose and Xylulose ribose and glucose The correct answer is Galactose and Fructose. Please explain why and discuss how to identify structural isomers.
- The ring structure of the carbohydrate glucose is provided below. Map any chiral centers with a 1.Galactose can exist as a cyclic hemiacetal because one of the alcohol groups reacts with the aldehyde. 1 2 3 4 он он о Н Он Он о CH2-CH-CH-CH-CH-C-H 6. CH2-OH OH C он 10 он C 8. H. H. OH Which carbon atom of the cyclic hemiacetal was originally a part of the aldehyde group? Carbon: Which alcohol group in the open-chain structure became a part of the cyclic hemiacetal? Alcohol:Indicate which of the terms monosaccharide, disaccharide, reducing sugar, anomers, enantiomers, and aldohexose applies to both members of each of the following pairs of substances. More than one term may apply to a given pair of substances. a-D-Glucose and a-D-galactose- Sucrose and cellobiose- Glyceraldehyde and dihydroxyacetone- D-Ribose and L-ribose-