College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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The potential difference between the accelerating plates of a TV set is about 30 kV. If the distance between the plates is 1.4 cm, find the magnitude of the uniform electric field in the region between the plates.
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- Chapter 22, Problem 053 /1 Your answer is partially correct. Try again. Two large parallel copper plates are 4.91 cm apart and have a uniform electric field of magnitude E = 3.82 N/C between them (see the figure). An electron is released from the negative plate at the same time that a proton is released from the positive plate. Neglect the force of the particles on each other and find their distance from the positive plate when they pass each other. Negative plate Positive plate UnitšT m Numbe the tolerance is +/-2%arrow_forwardAn electron is projected with an initial speed v0= 1.60 x 10^6 m/s into the uniform field between two parallel plates, both 2.00 cm in length and is separated by a distance of 1.00 cm. Assume that the field between plates is zero. The electron enters the field at a point midway between the plates. (a) If the electron just misses the upper plate as it emerges from the field, find the magnitude of the electric field. (b) Supposed that the electron is the replaced by a proton with the same initial speed v0. Would the proton hit one of the plates? If not, what would be the magnitude and direction of its vertical displacement as it exits the region between the plates?arrow_forwardAn electron is placed in a uniform electric field 26 nN/C directed north created by two horizontal parallel plates that are given 137 fm apart. The electron accelerates from rest, starting at the negative plate. What is the net force and acceleration acting on the electron? How long did it take the electron to get from one side of the plate to the other? Given: Required: Equation: Solution: Answer:arrow_forward
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