The position as a function of time of a squirrel running on a grass field is given in polar coordinates by r(t) = 20 + 30 (1 – e-0.1 ') r(1) θ()π (1- ε 02 1) = TT Plot as 1* subplot the trajectory (position) of the squirrel for 0st < 20s with a step of time 0.5s. Calculate numerically the speed of the squirrel given by v = r d8/dt. Create a 2nd subplot for speed of the squirrel v (numerical) as function of time for 0 st s 20s. Report the curve as green circle without line. In the same figure (2nd subplot), plot as black solid line the theoretical velocity given by the formula v =r de/dt as function of time for 0 st s 20s.

Solve both the questions!!!

Answer: 1.792e3 seconds

Use a software program or a graphing utility to solve the system of linear equations. (If there is no solution, enter NO SOLUTION. If the system has an infinite number of solutions, express X₁, X2, X3, X4, and X5 in terms of the parameter t.) X2 2x3 + 3x4 + 2x5 = 10 X1 + 3X1 + 3х2 - X3 + 2x1 + 2x₂ - X3 + 4x₁ + 4x2 + X3 8x1₁5x22x3 - (X1, X2, X3, X4, X5) = X4 + X5 = 11 X4 - 2x5 = 5 - 3x5 = 11 X4 + 2x5 22

A vertical photograph taken from a camera has calibrated focal length f153.206 mm contains an image point "a" of object point A at coordinates x=64.969 mm. y =-78.526 mm relative to the fiducial axes, Calibration sheet shoWS x = 0.247 mm and y= 0.238 mm as calibrated coordinates of principal point. Also, lists the radial lens distortion coefficients K1 2.99778547 x10-08 mm-2 K2-3.15091119 x10A-12 mm-4: K3 H 6.05776623 x10-17 mm-6. Compute the corrected coordinates for the image point "a"

Consider a system of linear equations in the form of BX = A, where x is the unknown vector. Which of the following can be used to solve for x? -_-_-_-_-_-_-_-_-_-_-_-_-_-_- .….….….…..……….….….….…..….….…..…….….…….….….…... Select one: O a. X = inv(B)./A b. X = BIAOXO DXD OXO OXO OXO OHO C. X =A\B Brid ○ d. X = B./A 0²% 0²% 0²% 0²% 0²:0²: e. X = inv(A)*B

F4

20, Solve the equations Ax = b, where

You solve a non-singular system of 1,000 linear equations with 1,000 unknowns. Your code uses the Gauss-Jordan algorithm with partial pivoting using double precision numbers and arithmetics. Why would the 2-norm of the residual of your solution not be zero?

Water flow at a water treatment plant is often in the units of gallons per day.   However, in pipe flows, we often need to express water flow in feet per second.   Convert 17,200 gallons per day to feet per second. Round your answer to the nearest ten-thousandth feet/second (i.e., 0.0000).