MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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- If n=14, (x-bar)=46, and s=18, construct a confidence interval at a 80% confidence level. Assume the data came from a normally distributed population. Give your answers to one decimal place.arrow_forwardDetermine the point estimate of the population mean and margin of error for the confidence interval. Lower bound is 15, upper bound is 27. The point estimate of the population mean is The margin of error for the confidence interval isarrow_forwardDetermine whether the statement below makes sense or does not make sense. Explain clearly. Based on our sample, the 95% confidence interval for the mean amount of television watched by adults in a nation is 2.9 to 4.3 hours per day. Therefore, there is 95% chance that the mean for all adults in the nation will fall somewhere in this range and a 5% chance that it will not. C Choose the correct answer below. O A. The statement makes sense. There is 5% probability that the confidence interval limits do not contain the true value of the sample mean, so the probability it does not contain the true value of the population mean is also 5%. O B. The statement does not make sense. The population mean is a fixed constant that either falls within the confidence interval or it does not. There is no probability associated with this. O C. The statement does not make sense. The probability the population mean is greater than the upper limit is 5% and the probability it is less than the lower limit is…arrow_forward
- magine that you conduct a study and estimate that the prevalence of hypertension among employees of a company. Your estimated prevalence is 24%. You also calculate a margin of error for a 95% confidence interval associated with this prevalence estimate of 3%. What would be the 95% confidence interval for the prevalence calculated from this study?arrow_forwardDetermine the point estimate of the population mean and margin of error for the confidence interval. Lower bound is 21, upper bound is 29. The point estimate of the population mean is nothing.arrow_forwardA confidence interval for a mean is (-11, 10). This interval would be wider if The sample mean was larger or the variability of the data was larger. The investigator wanted to be more confident of their results, or there was more information. The variability of the data was small, or the sample mean was larger. The variability of the data was larger, or the investigator wanted to be more confident. None of the above.arrow_forward
- Mark each statement TRUE or FALSE. For these problems, assume that to estimate average time spent waiting at a restaurant, you sample 10 people and you get a 95% confidence interval of (5, 7) in minutes. If you increase sample size, the width of your confidence interval increases. If you increase confidence level, the width of your confidence interval increases.arrow_forwardHow do I solve this?arrow_forwardA statistics practitioner took a random sample of 47 observations from a population whose standard deviation is 32 and computed the sample mean to be 97. Note: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits. A. Estimate the population mean with 95% confidence. Confidence Interval = B. Estimate the population mean with 90% confidence. Confidence Interval = C. Estimate the population mean with 99% confidence. Confidence Interval =arrow_forward
- Determine the point estimate of the population mean and margin of error for the confidence interval. Lower bound is 1919, upper bound is 2525.The point estimate of the population mean is nothing.Enter your answer in the answer box and then click Check Answer.1arrow_forwardA statistics practitioner took a random sample of 59 observations from a population whose standard deviation is 32 and computed the sample mean to be 95. Note: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits. A. Estimate the population mean with 95% confidence. Confidence Interval = B. Estimate the population mean with 90% confidence. Confidence Interval= C. Estimate the population mean with 99% confidence. Confidence Interval=arrow_forwardTranslate the statement into a confidence interval. Approximate the level of confidence. In a survey of 1011 parents of children ages 8-14, 70% say they are willing to get a second or part-time job to pay for their children's college education and 42% say they lose sleep worrying about college costs. The survey's margin of error is +2%. Use the results from the survey about getting a second or part-time job. The confidence interval for the proportion is ( D (Round to three decimal places as needed.)arrow_forward
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