The plates of a parallel-plate capacitor have a separation of 4.28 mm, and eachhas an area of 16.2 cm². Each plate carries a charge of magnitude 5.35x10-8 C.The plates are in vacuum.For related problemsolving tips and strategies, you may want to view a VideoTutor Solution of Properties of a parallel-plate capacitor.What is the capacitance?Express your answer with the appropriate units.C = 3.35x10-12 FSubmitCorrectSet Up: C =Part BPrevious AnswersSolve: C = €0€0 AdV= 2.3107Part CE =What is the potential difference between the plates?Express your answer with the appropriate units.C == €010uAValueand V = Ed.1.62×10-³ m²4.28x10-³ mSubmit Previous Answers Request Answer- 3.35 x 10-12 FVX Incorrect; Try Again; 5 attempts remainingWhat is the magnitude of the electric field between the plates?Express your answer with the appropriate units.?Units?

Given Separation between the each plate is given as d=4.28 mm=4.28×10-3 m Area of each plate is…

The plates of a parallel-plate capacitor have a separation of 4.28 mm, and each has an area of 16.2 cm². Each plate carries a charge of magnitude 5.35x10-8 C. The plates are in vacuum. For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Properties of a parallel-plate capacitor. What is the capacitance? Express your answer with the appropriate units. C = 3.35x10-12 F Submit ✓ Correct Part B Previous Answers Set Up: C =- C € A d Solve: C = 0 = €0 V= 2.310-10 What is the potential difference between the plates? Express your answer with the appropriate units. Part C E= and V = Ed. Submit Previous Answers Request Answer 1.62x10-³ m² 4.28x10-³ m UA X Incorrect; Try Again; 5 attempts remaining Value V 3 3.35 x 10-12 F What is the magnitude of the electric field between the plates? Express your answer with the appropriate units. ? Units ?

The plates of a parallel-plate capacitor have a separation of 4.28 mm, and each has an area of 16.2 cm². Each plate carries a charge of magnitude 5.35x10-8 C. The plates are in vacuum. For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Properties of a parallel-plate capacitor. What is the capacitance? Express your answer with the appropriate units. C = 3.35x10-12 F Submit ✓ Correct Part B Previous Answers Set Up: C =- C € A d Solve: C = 0 = €0 V= 2.310-10 What is the potential difference between the plates? Express your answer with the appropriate units. Part C E= and V = Ed. Submit Previous Answers Request Answer 1.62x10-³ m² 4.28x10-³ m UA X Incorrect; Try Again; 5 attempts remaining Value V 3 3.35 x 10-12 F What is the magnitude of the electric field between the plates? Express your answer with the appropriate units. ? Units ?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

A spherical capacitor consists of a spherical conducting shell of radius bb and charge −Q concentric with a smaller conducting sphere of radius a and charge +Q. Enter an expression for the capacitance of this device in terms of Coulomb's Constant ke (just type "k" with no subscript) and the two radii a and b. HINT: you may need to apply a negative sign to your final expression to be sure the capacitance comes out positive! Look at your answer and think about which radii is larger.
how to get 1.25nF in this problem A spherical capacitor has an inner sphere of radius 10 cm and an outer sphere of radius 14 cm. The outer sphere is earthed and the inner sphere is given a charge of 2.5 µC. The space between the concentric spheres is filled with a liquid of dielectric constant 32. Determine the capacitance of the capacitor.
An air-filled parallel-plate capacitor with a plate separation of 2.95 mm has a capacitance of 100 pF. What is the area of one of the capacitor's plates? Be careful about units. The plate area, A = = What is the magnitude of electric field in the capacitor if it is charged to Q = 6.2 nC? The electric field, E = Units Select an answer ✓ Units Select an answer ✓ What is the energy density that corresponds to this electric field? The energy density, U₁ = Units Select an answer ✓
The plates of a parallel-plate capacitor are separated by 0.12 mm. The permittivity of a vacuum is 8.85419 × 10-¹2 C²/N. m². If the space between the plates is air, what plate area is required to provide a capacitance of 9 pF? Answer in units of cm².
Consider a cylindrical capacitor with inner radius r1 = 8.1 cm, outer radius r2 = 14.3 cm, and length L = 16.7 cm. A dielectric with dielectric constant κ = 53 fills the volume between the two cylinders. The capacitor is connected to a 106.6 V battery and is fully charged. What is the charge on the capacitor? Express your answer in Coulombs to 3 significant figures.
2. In lecture we saw parallel plate and coaxial cylindrical capacitors. We can also have spherical capacitors! Consider a conducting sphere with radius a and total charge Q enclosed within a concentric hollow spherical conducting shell with radius 6 and a total charge -Q. For parts a) and b), the region between the conductors (a < r < b) is empty (vacuum). a) Find an expression for the capacitance of a spherical capacitor. Is it geometric as we expect? b) Find an expression for the energy stored by the spherical capacitor first by using U (just replace C by your answer from part a)) and second by integrating the energy density u of the electric field over all space. Do your answers agree? = 20 c) Now suppose the region between the conductors is filled with a dielectric with dielectric constant ‹ = 3. What is the bound charge per unit area near the inner sphere (at r = = a) and near the outer shell (at r = b)? What is the total bound charge at each surface (expressed as a fraction of…
A capacitor is constructed of two parallel plates of side l separated by a distance d. A material of dielectric constant k is inserted a distance x as shown in the figure. The potential difference between the plates is V. The energy stored by the system is: a. U=(1/2)(ϵ0l/d)(x+l(k−1))V2 b. U=(1/2)(ϵ0l/d)(l−x(k−1))V2 c. U=(1/2)(ϵ0l/d)(x−l(k−1))V2 d. U=(1/2)(ϵ0l/d)(l+x(k−1))V2
A parallel-plate air capacitor with a capacitance of 248 pF has a charge of magnitude 0.151 µC on each plate. The plates have a separation of 0.337 mm. What is the area of each plate? Answer in square meters and use three significant digits.
A parallel-plate capacitor is constructed by filling the space between two square plates with a block of three dielectric materials, as shown in the figure below. You may assume that ℓ ≫ d. A parallel-plate capacitor is comprised of two square plates with sides of length ℓ and separation distance d. There are three dielectric materials in the space between the capacitor plates. A material with length ℓ⁄2, height d, and dielectric constant ?1 fills the left half of the space. A material with length ℓ⁄2, height d⁄2, and dielectric constant ?2 fills the top right quarter of the space. A material with length ℓ⁄2, height d⁄2, and dielectric constant ?3 fills the bottom right quarter of the space. (a) Find an expression for the capacitance of the device in terms of the plate area A and d, ?1, ?2, and ?3. (Use the following as necessary: ?1, ?2, ?3, ?0, A and d.)C = (b) Calculate the capacitance using the values A = 1.30 cm2, d = 2.00 mm, ?1 = 4.90, ?2 = 5.60, and ?3 = 2.50.
A. What is the capacitance (in µF) of a parallel plate capacitor having plates of area 1.25 m2 that are separated by 0.0230 mm of neoprene rubber? B.What charge (in µC) does it hold when 9.00 V is applied to it?
A parallel-plate air capacitor has a capacitance of 920 pF. The charge on each plate is 3.90 μC. Part A What is the potential difference between the plates? Express your answer with the appropriate units. V = Submit Part B V = 123+ Part C Submit AU = Value If the charge is kept constant, what will be the potential difference between the plates if the separation is doubled? Express your answer with the appropriate units. 123+ Submit Request Answer Value Units 3 123+ Value 3 ? Request Answer ( 3 ? How much work is required to double the separation? Express your answer with the appropriate units. Units - C ? Units Request Answer
The plates of a parallel-plate capacitor are 3.22 mm apart, and each has an area of 9.92 cm². Each plate carries a charge of magnitude 4.50x10-8 C. The plates are in vacuum. ▼ What is the capacitance? Express your answer with the appropriate units. C = Submit Part B PHÅ V = Value Request Answer What is the potential difference between the plates? Express your answer with the appropriate units. 98 Value C μᾶ Units Units ? ?