The plasticity of a polyethylene is affected by the concentration of a solution. When low concentration of the solution is used, the true mean plasticity is 55. And when high concentration is used, the mean plasticity is 62. The standard deviation of plasticity is 4 regardless of concentration of the solution. If two random samples of size 18 are taken, find the probability that Xnigh – X low 2 5. Include your solutions. O a. Probability is about 7% O b. Probability is about 98% O c. Probability is about 93% O d. NONE
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- The specification limits for a product are 8 cm and 10 cm. A process that produces the product has a mean of 8.5 cm and a standard ?deviation of 0.2 cm. What is the process capability, Cpk .a 1.67 .b 3.33 .C None of them .d 0.83 .e 2.50Assume that the readings on the thermometers are normally distributed with a mean of 0 degrees and standard deviation of 1.00degrees C. Assume 2.4% of the thermometers are rejected because they have readings that are too high and another 2.4% are rejected because they have readings that are too low. Draw a sketch and find the two readings that are cutoff values separating the rejected thermometers from the others. A. The cutoff values are degrees. (Use a comma to separate answers as needed. Round to two decimal places as needed.)Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find the bone density test scores that can be used as cutoff values separating the lowest 6% and highest 6%, indicating levels that are too low or too high, respectively. Sketch the region containing the lowest 6% and highest 6%. Choose the correct graph below. O A. Za Za E OB. The bone density scores are (Use a comma to separate answers as needed. Round to two decimal places as needed.) Za Za OD. Za Za ♫
- Assume the readings on thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. Find the probability that a randomly selected thermometer reads between −2.25 and −1.65 and draw a sketch of the region. Click to view page 1 of the table. LOADING... Click to view page 2 of the table. LOADING... Question content area bottom Part 1 Sketch the region. Choose the correct graph below. A. -1.65-2.25 A graph with a bell-shaped curve, divided into 3 regions by 2 lines from top to bottom, both on the left side. Moving from left to right, the region left of the first line is shaded. The z-axis below this line is labeled negative 2.25. The z-axis below the second line is labeled negative 1.65. B. -1.65-2.25 A graph with a bell-shaped curve, divided into 3 regions by 2 lines from top to bottom, both on the left side. The region between the 2 lines is shaded. Moving from…Scores for men on the verbal portion of the SAT-I test are normally distributed with a mean of 545 and a standard deviation of 112 . If 16 men are randomly selected, find the probability that their mean score is at least 590. a. Define the parameter A. x overbar equals The mean score of 16 randomly selected men B. x overbar equals The score of a randomly selected man b. State the mean of x overbar : nothing c. State the standard deviation of x overbar : nothing (use 2 decimal places) d. Find the z-score: nothing (use 2 decimal places) e. Find the probability: nothing (use 4 decimal places)Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. Find the probability that a given score is between - 2.18 and 3.86 and draw a sketch of the region. Sketch the region. Choose the correct graph below. O A. В. OC. O D. -2.18 3.86 2.18 3.86 -2.18 3.86 -2.18 3.86 The probability is (Round to four decimal places as needed.) Click to select your answer(s). 山T00④ NOV 2. 1377 14 X P W MacBook Air esc 80 888 F3 F4 F7 FB F9 F10 $4 & 4 80 Q E Y A F G H. K /2x cv C V B D. 林 wwww wwwww
- We are to estimate the mean of a population, u. The population variance is o. Both the population mean and varíance are unknown. I have twO suggestions as the estimators shown below, A and A2. Tell which one is better. Show all calculations and arguments. Az=Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. Find the probability that a given score is between -2.05 and 3.87 and draw a sketch of the region. Sketch the region. Choose the correct graph below. OA. OB. OC. OD. -2.05 3.87 2.05 3.87 -2.05 3.87 -2.05 3.87 The probability is (Round to four decimal places as needed.)In one of the Stat 2 sections, the students in the section have an average height of 64 inches, with a standard deviation of 3 inches. The GSI happens to be 68 inches. Express the height of the GSI in standard units, relative to the students in the section. Choose the answer below that is closest. Group of answer choices 1.67 3.0 1.5 1.33 4.0 PreviousNext
- Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P67, the 67-percentile. This is the temperature reading separating the bottom 67% from the top 33%. P67 Ры °C %3DBill Alther is a zoologist who studies Anna's hummingbird (Calypte anna). (Reference: Hummingbirds, K. Long, W. Alther.) Suppose that in a remote part of the Grand Canyon, a random sample of six of these birds was caught, weighed, and released. The weights (in grams) were as follows. 3.7 2.9 3.8 4.2 4.8 3.1 The sample mean is = 3.75 grams. Let x be a random variable representing weights of hummingbirds in this part of the Grand Canyon. We assume that x has a normal distribution and ? = 0.64 gram. Suppose it is known that for the population of all Anna's hummingbirds, the mean weight is ? = 4.30 grams. Do the data indicate that the mean weight of these birds in this part of the Grand Canyon is less than 4.30 grams? Use ? = 0.10. Level of significance = .10 Null and alternate hypotheses. - H0: ? = 4.3 g; H1: ? < 4.3 g; left-tailed Sampling Distribution - The standard normal, since we assume that x has a normal distribution with known ? Compute the z value of the sample test…The weight of a small Starbucks coffee is a normally distributed random variable with a mean of 415 grams and a standard deviation of 23 grams. Find the weight that corresponds to each event. (Use Excel or Appendix C to calculate the z-value. Round your final answers to 2 decimal places.) a. Highest 20 percent b. Middle 60 percent to c. Highest 80 percent d. Lowest 15 percent