The pH of a finished water from a softening process is 10.74. What amount of 0.002 N sulfuric acid, in milliliters, is required to neutralize 1 L of the finished water? Assume the buffering capacity is zero.
The pH of a finished water from a softening process is 10.74. What amount of 0.002 N sulfuric acid, in milliliters, is required to neutralize 1 L of the finished water? Assume the buffering capacity is zero.
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter11: Solutions
Section: Chapter Questions
Problem 26P
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- The pH of a finished water from a softening process is 10.74. What amount of 0.002 N sulfuric acid, in milliliters, is required to neutralize 1 L of the finished water? Assume the buffering capacity is zero.
Expert Solution
Step 1
The pH of the finished water from a softening process is 10.74, greater than 7. Hence the solution is basic in nature. The basic solution is neutralized by sulfuric acid. To calculate the amount of required acid first of all we calculate the hydroxide ion concentration in the given solution.
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