The pH for 0.0850 M solution of CcH:CH:COOH is 2.68. Determine the value of Ka for CaH.CH:COOH. NEXT > Based on the given values, fill in the ICE table to determine concentrations of all reactants and products. C.H.CH:COOH(aq) H:O(1) H.O(aq) + C.H,CH:COO"(aq) Initial (M) Change (M) Equilibrium (M) 2 RESET 2.1 x 10 -21 x 10 0.0829 0.0850 2.68 -2.68 -0.0829 0.428 -0.428

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The pH for 0.0850 M solution of C&H:CH2COOH is 2.68. Determine the value of Ka for CSH$CH2COOH.
NEXT
>
Based on the given values, fill in the ICE table to determine concentrations of all reactants and products.
C6H:CH:COOH(aq)
H:O(1)
H:O*(aq)
C6H:CH:COO (aq)
+
+
Initial (M)
Change (M)
Equilibrium (M)
2 RESET
0.0850
2.68
-2.68
2.1 x 10
-2.1 x 10
0.0829
-0.0829
0.428
-0.428
+
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Transcribed Image Text:A Dashboard 101 Chem101 b Answered: At a particular temper X A aрp.101edu.co Question 4 of 23 Submit The pH for 0.0850 M solution of C&H:CH2COOH is 2.68. Determine the value of Ka for CSH$CH2COOH. NEXT > Based on the given values, fill in the ICE table to determine concentrations of all reactants and products. C6H:CH:COOH(aq) H:O(1) H:O*(aq) C6H:CH:COO (aq) + + Initial (M) Change (M) Equilibrium (M) 2 RESET 0.0850 2.68 -2.68 2.1 x 10 -2.1 x 10 0.0829 -0.0829 0.428 -0.428 + 10:35 PM P Type here to search 65°F Mostly sunny 10/31/2021
A Dashboard
101 Chem101
b Answered: At a particular temper X
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Question 4 of 23
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The pH for 0.0850 M solution of C6HSCH:COOH is 2.68. Determine the value of Ka for C&H;CH2COOH.
PREV
2
Based on your ICE table and definition of Ka, set up the expression for Ka and then evaluate it. Do not combine or simplify terms.
Ka =
2 RESET
[0]
[0.0850]
[2.68]
[2.1 x 10
[0.0829]
[0.428]
[4.79 x 10-1
1.9 x 104
40
0.025
5.3 x 105
+
10:35 PM
P Type here to search
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Transcribed Image Text:A Dashboard 101 Chem101 b Answered: At a particular temper X A aрp.101edu.co Question 4 of 23 Submit The pH for 0.0850 M solution of C6HSCH:COOH is 2.68. Determine the value of Ka for C&H;CH2COOH. PREV 2 Based on your ICE table and definition of Ka, set up the expression for Ka and then evaluate it. Do not combine or simplify terms. Ka = 2 RESET [0] [0.0850] [2.68] [2.1 x 10 [0.0829] [0.428] [4.79 x 10-1 1.9 x 104 40 0.025 5.3 x 105 + 10:35 PM P Type here to search 65°F Mostly sunny 10/31/2021
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