If the pH of a 0.0850 M solution of HB1O2 is 2.29, then what is the value for the acidity constant, Ka, of HBrO2? HB1O2(aq) + H20(I) H3O*(aq) + Br0, (aq) K¸ = ?

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**Problem Statement:**

If the pH of a 0.0850 M solution of HBrO₂ is 2.29, then what is the value for the acidity constant, Kₐ, of HBrO₂?

**Chemical Equation:**

\[ \text{HBrO}_2(\text{aq}) + \text{H}_2\text{O}(\text{l}) \rightleftharpoons \text{H}_3\text{O}^+(\text{aq}) + \text{BrO}_2^−(\text{aq}) \]

\[ K_a = ? \]

**Calculation Pathway:**

To find the \( K_a \), use the equation for the equilibrium constant for acids:

\[ K_a = \frac{[\text{H}_3\text{O}^+][\text{BrO}_2^-]}{[\text{HBrO}_2]} \]

**Provided Values:**

- Initial concentration of HBrO₂: 0.0850 M
- pH: 2.29

**Steps for Calculation:**

1. **Calculate the Hydronium Ion Concentration (\([\text{H}_3\text{O}^+]\)):**

   From the pH value:

   \[ [\text{H}_3\text{O}^+] = 10^{-\text{pH}} = 10^{-2.29} \]

2. **Determine Changes in Concentrations:**

   - Initial concentration of HBrO₂: 0.0850 M
   - Change in concentration of HBrO₂ and formation of \(\text{H}_3\text{O}^+\) = \(x\)

3. **Expression for Kₐ:**

   Substitute the concentrations into the equilibrium expression to solve for \( K_a \).

4. **Conclusion and Analysis:**

Complete the calculation and then answer the following:

*Given the information above, is the bromite ion, \(\text{BrO}_2^-\), a strong base, a weak base, or not basic in water?* 

Use the result of the \( K_a \) value to determine the basicity of \(\text{BrO}_2^-\).
Transcribed Image Text:**Problem Statement:** If the pH of a 0.0850 M solution of HBrO₂ is 2.29, then what is the value for the acidity constant, Kₐ, of HBrO₂? **Chemical Equation:** \[ \text{HBrO}_2(\text{aq}) + \text{H}_2\text{O}(\text{l}) \rightleftharpoons \text{H}_3\text{O}^+(\text{aq}) + \text{BrO}_2^−(\text{aq}) \] \[ K_a = ? \] **Calculation Pathway:** To find the \( K_a \), use the equation for the equilibrium constant for acids: \[ K_a = \frac{[\text{H}_3\text{O}^+][\text{BrO}_2^-]}{[\text{HBrO}_2]} \] **Provided Values:** - Initial concentration of HBrO₂: 0.0850 M - pH: 2.29 **Steps for Calculation:** 1. **Calculate the Hydronium Ion Concentration (\([\text{H}_3\text{O}^+]\)):** From the pH value: \[ [\text{H}_3\text{O}^+] = 10^{-\text{pH}} = 10^{-2.29} \] 2. **Determine Changes in Concentrations:** - Initial concentration of HBrO₂: 0.0850 M - Change in concentration of HBrO₂ and formation of \(\text{H}_3\text{O}^+\) = \(x\) 3. **Expression for Kₐ:** Substitute the concentrations into the equilibrium expression to solve for \( K_a \). 4. **Conclusion and Analysis:** Complete the calculation and then answer the following: *Given the information above, is the bromite ion, \(\text{BrO}_2^-\), a strong base, a weak base, or not basic in water?* Use the result of the \( K_a \) value to determine the basicity of \(\text{BrO}_2^-\).
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