The part with the switch and two resistors R1 in parallel of the circuit below dissipates the same amount of power whether or not the switch is closed. Neglecting any internal resistance in the battery, determine the value of R1 in terms of R.

The two figure panels show two ways to connect a real (non-ideal) voltmeter and a real ammeter in a circuit to calculate the resistance R. The internal resistance of the voltmeter is Rv and the internal resistance of the ammeter is Ra. The current flows from left to right in both panels, and the potential difference Vac between points a and c in both panels is the same. In panel (a) 
the voltmeter reads Vac = 12.1 V and the ammeter reads I1 = 0.098 A. In panel (b) the voltmeter reads Vab = 12.0 V and the ammeter reads I2 = 0.100 A.   I need help with Part E.

The figure below shows a capacitor, with capacitance C = 35.0 μF, and a resistor, with resistance R = 40.0 kn, connected in series to a battery, with = 13.0 V. The circuit has a switch, which is initially open. + R (a) What is the circuit's time constant (in s)? (b) After the switch is closed for one time constant, how much charge (in C) is on the capacitor?

Three resistors, R₁ = 232, R₂=3502, and R,=4552, are connected to a capacitor of capacitance C=32μF and a battery with emf 8=14V as shown in the figure below. The capacitor is initially uncharged when the switch is closed at t-0. Determine the current running on R, on the capacitor at r=0. Express your answer in units mA using zero decimal places. S w ++ R₁ www C ww R3

Consider the circuit shown below. The resistor has R= 40 ohms and the capacitor has C= 6 x10^-6 F. Initially the switch is open and there is no charge on the capacitor and no current in the resistor. At a time after the switch is closed the current in the resistor is 2 A and the charge on the capacitor is q= +3.00 x 10^-4 C. What is the emf of the battery?

Consider the circuit shown in the figure. Suppose the four resistors in this circuit have the values R1 = 12 Ω, R2 = 7.1 Ω , R3 = 7.1 Ω, and R4 = 13 Ω, and that the emf of the battery is ε = 18 V. Find the current through each resistor and the power dissipated in the circuit.

The following equations describe an electric circuit. −I1(247 Ω) + 5.80 V − I2(381 Ω)  =  0 I2(381 Ω) + I3(150 Ω) − 3.10 V  =  0 I1 + I3 − I2  =  0 Calculate the unknowns (in mA). With respect to the 5.8 V battery, consider current moving toward the positive pole as positive and current moving toward the negative pole as negative. THE FOLLOWING GIVEN ANSWERS WERE INCORRECT: I1= -10.008 mA I2= -0.868 mA I3= 0.139 mA

Problem 5: A current of I- 2.6 A passes through the circuit shown, where R- 65 3R 5R V) 2R 6R 2R 7R 5R 10R Otheexpertta.com Part (a) In terms of R, I, and numeric values, write an expression for the voltage of the · source, V. Part (b) What is the voltage, V in volts? tan( sin() cotanO a acos cosh0t cosO asin() acotan 4 5 6 sinh() cotanhO *1 23 0 tanh0c O Degrees O Radians CLEAR BACKSPACE

A student in the laboratory connects a 17 Ω resistor, a 26 Ω resistor, and a 34 Ω resistor in parallel and then connects the arrangement to a 46 V dc source. (a) What is the current? A(b) What is the power? W