Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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- show all steps/solution plzarrow_forwardPlease show all work!arrow_forwardThe beam is subjected to an internal moment of M = 122 kN.m (Figure 1) Figure 30 mm, C. B 150 mm. M 150 mm 300 mm. 2 4 30 mm 1 of 1 ▼ Part A Determine the bending stress developed at point A. Express your answer to three significant figures and include the appropriate units. Enter negative value in the case of compression and positive value in the case of tension. A=148 Submit Part B μÁ MPa www Previous Answers Request Answer R= 624 MPa X Incorrect; Try Again; 4 attempts remaining ? Determine the bending stress developed at point B. Express your answer to three significant figures and include the appropriate units. Enter negative value in the case of compression and positive value in the case of tension.arrow_forward
- Please answer quickly. Thanks!arrow_forwardWhat is the maximum length of a uniformly loaded, simply supported beam based on the maximum allowable stresses, its normal stress of 90MPa and its shear stress of 100MPa? The uniform load is 10kN/m. The area is b = 20mm and h = 80mmarrow_forward5. A 4-point bending test is performed on a beam of length L = 1 m. A load of P = 2000 N is applied across two loading points a distance a = 0.4 m from the sides of the beam. If the beam has a radius of r = 1 cm and a yield strength of σ = 250 MPa, does the bar yield? If it's an elastic-perfectly plastic material, does it fail all the way through the thickness of the bar? What would the yield strength of the material need to be if we wanted a factor of safety of 1.5?arrow_forward
- A steel I-beam has the dimensions shown in the figure and is subjected to a shear force V=80 kN. Determine the shear stress at point P, t=VQ/It (MPa). Also, convert the answer from MPa to psi. Recall, 1 MPa = 145.04 psi. 20 mm 100 mm A 20 mm 15 mm 100 mm P 20 mm N.A. V=80 kN N 300 mm 20mm P 20mm 100mm 15mm 300mmarrow_forwardThe beam shown below is made of air-dried Douglas fir (E = 1900 ksi) with an allow- able flexural stress of 2000 psi, an allowable shearing stress of 85 psi, and an allowable deflection of 0.8 in. Select the lightest standard structural timber that can be used to support the load shown in the figure. 12 ft 8000 lb B 12 ft Carrow_forward
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