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The number of gallons, H (t), of a pollutant in a pond changes at a rate of H' (t) = 3 – 5e-0.8√/t gallons per day, where t is measured in days. There are 100 gallons of pollutant in the pond at t = 0. Is the amount of pollutant increasing or decreasing at t = 5? O Decreasing because P' (5) < 0 O Increasing because P (5) > 0 Decreasing because P (5) <0 O Increasing because P' (5) > 0.

The number of gallons, H (t), of a pollutant in a pond changes at a rate of H' (t) = 3 – 5e-0.8√/t gallons per day, where t is measured in days. There are 100 gallons of pollutant in the pond at t = 0. Is the amount of pollutant increasing or decreasing at t = 5? O Decreasing because P' (5) < 0 O Increasing because P (5) > 0 Decreasing because P (5) <0 O Increasing because P' (5) > 0.

Calculus For The Life Sciences
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter3: The Derivative
Section3.3: Rates Of Change
Problem 30E: If the instantaneous rate of change of f(x) with respect to x is positive when x=1, is f increasing...
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The number of gallons, H (t), of a pollutant in a pond changes at a rate of H' (t) = 3 – 5e−0.8√t gallons per day, where t is measured in days. There are 100 gallons of pollutant in the pond at t = 0. Is the amount of pollutant increasing or decreasing at t - 5? Decreasing because P' (5) < 0 Increasing because P (5) > 0 Decreasing because P (5) < 0 O Increasing because P' (5) > 0.
Transcribed Image Text:The number of gallons, H (t), of a pollutant in a pond changes at a rate of H' (t) = 3 – 5e−0.8√t gallons per day, where t is measured in days. There are 100 gallons of pollutant in the pond at t = 0. Is the amount of pollutant increasing or decreasing at t - 5? Decreasing because P' (5) < 0 Increasing because P (5) > 0 Decreasing because P (5) < 0 O Increasing because P' (5) > 0.
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