The number of ants per acre in the forest is normally distributed with mean 42,000 and standard deviation 12,217. Let X = number of ants in a randomly selected acre of the forest. Round all answers to 4 decimal places where possible. a. What is the distribution of X? XN( 42,000 b. Find the probability that a randomly selected acre in the forest has fewer than 46,519 ants. 12,217 c. Find the probability that a randomly selected acre has between 30,262 and 44,398 ants. d. Find the first quartile. ants (round your answer to a whole number)

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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The number of ants per acre in the forest is normally distributed with a mean of 42,000 and a standard deviation of 12,217. Let \(X\) represent the number of ants in a randomly selected acre of the forest. Round all answers to four decimal places where possible.

a. What is the distribution of \(X\)? \(X \sim N(\) \(\boxed{42,000}\) \(,\) \(\boxed{12,217}\) \()\)

b. Find the probability that a randomly selected acre in the forest has fewer than 46,519 ants.  
\(\boxed{}\)

c. Find the probability that a randomly selected acre has between 30,262 and 44,398 ants.  
\(\boxed{}\)

d. Find the first quartile. \(\boxed{}\) ants (round your answer to a whole number)

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Transcribed Image Text:**Transcription for Educational Website:** --- The number of ants per acre in the forest is normally distributed with a mean of 42,000 and a standard deviation of 12,217. Let \(X\) represent the number of ants in a randomly selected acre of the forest. Round all answers to four decimal places where possible. a. What is the distribution of \(X\)? \(X \sim N(\) \(\boxed{42,000}\) \(,\) \(\boxed{12,217}\) \()\) b. Find the probability that a randomly selected acre in the forest has fewer than 46,519 ants. \(\boxed{}\) c. Find the probability that a randomly selected acre has between 30,262 and 44,398 ants. \(\boxed{}\) d. Find the first quartile. \(\boxed{}\) ants (round your answer to a whole number) ---
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