MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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The average American man consumes 9.7 grams of sodium each day. Suppose that the sodium consumption of American men is
a. What is the distribution of X? X ~ N
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- The frequency distribution was obtained using a class width of 0.5 for data on cigarette tax rates. Use the frequency distribution to approximate the population mean and population standard deviation. Compare these results to the actual mean u = $1.727 and standard deviation o = S1.041. E Click the icon to view the frequency distribution for the tax rates. Frequency distribution of cigarette tax rates The population mean is $ Tax Rate 0.00-0.49 0.50-0.99 1.00-1,49 1.50-1.99 2.00-2.49 2.50-2.99 3.00-3.49 3.50-3.99 Frequency D (Round to three decimal places as needed.) 5 15 The population standard deviation is S (Round to three decimal places as needed.) Compare these results to the values found using the actual data. O A. The grouped mean is slightly larger, while the grouped standard deviation is slightly smaller. O B. The grouped values are both slightly larger. O C. The grouped values are both slightly smaller. O D. The grouped mean is slightly smaller, while the grouped standard…arrow_forwardPsychology students at a university completed the Dental Anxiety Scale questionnaire. Scores on the scale range from 0 (no anxiety) to 20 (extreme anxiety). The mean score was 11 and the standard deviation was 3.5. Assume that the distribution of all scores on the Dental Anxiety Scale is normal with u = 11 and o = 3.5. Complete parts a through c. Click here to view a table of areas under the standardized normal curve. a. Suppose you score a 18 on the Dental Anxiety Scale. Find the z-value for this score. z= 2 (Round to the nearest hundredth as needed.) b. Find the probability that someone scores between 10 and 15 on the Dental Anxiety Scale. P(10sxs 15) = (Round to four decimal places as needed.) c. Find the probability that someone scores above 17 on the Dental Anxiety Scale. P(x> 17) =| (Round to four decimal places as needed.)arrow_forwardssume that adults have IQ scores that are normally distributed with a mean of 100 and a standard deviation of 15 (as on the Wechsler test). Find the following: The Z-value that separates the bottom 18% from the others. The Z-Value for the 95 percentile. What is the IQ score that separates the bottom 18% from the others? The 95 percentile is? A. 113.725 B. -.92 C. 75.325 D. -.915 E. 1.645 F. 86.275 G. 124.675 H. .915arrow_forward
- subpart. plz help with the last questionarrow_forwardFind the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. Click to view page 1 of the table. LOADING... Click to view page 2 of the table. LOADING... 90 A graph with a bell-shaped curve, divided into 2 regions by a vertical line. The vertical line extends from the bell curve to the x-axis, and is located on the left half, under the curve. The region on the left of this line is shaded. The x-axis below the vertical line is labeled 90. Question content area bottom Part 1 The area of the shaded region is enter your response here. (Round to four decimal places as needed.)arrow_forwardAssume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find P15, the 15th percentile. This is the bone density score separating the bottom 15% from the top 85%. Which graph represents P15? Choose the correct graph below. O A. 1 P15 Q The bone density score corresponding to P15 is (Round to two decimal places as needed.) B. P15 Q Q -C*** O C. A P15 O D. A P15 Qarrow_forward
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