Chemistry
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Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Transcribed Image Text:Using the Kt and Kb equations with electrolytes
The normal freezing point of a certain liquid X is 5.10 °C, but when 0.12 kg of alanine (C,H,NO,) are dissolved in 800. g of X the
solution freezes at 0.9 °C instead. Use this information to calculate the molal freezing point depression constant K, of X.
Round your answer to 2 significant digits.
°C-kg
K, =
mol
Explanation
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Step 1
given, the mass of C3H7NO2 = 0.12kg = 0.12 g
mass of solvent X = 800. g = 0.800 kg
molar mass of C3H7NO2 = 89 g mol-1
freezing point of liquid X = 5.10 oC
freezing point of solution = 0.9 oC
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