The New York Times conducted a nationwide poll of 1048 randomly selected 13- to 17-year-olds. to estimate the proportion of 13- to 17-year-olds who have a television in their room. We can consider the sample to be a simple random sample. Of these 1048 teenagers, 692 had a television in their room. Give a 95% confidence interval for the proportion of all people in this age group who had a TV in their room at the time of the poll, and interpret what your interval means in context.

Q: There are 3000 beads of various colors in a jar. In a sample of 125 beads, 40% were red. Calculate…

A:

Q: In your work for a real estate company, you find that in a sample of 1762 home buyers, 722 found…

A: Given Data: x=722 n=1762   p^=7221762=0.4098

Q: In a survey of 3084 adults aged 57 through 85 years it was found that 81.9% of them used at least…

A: Given : Sample Size, n = 3084 confidence level,c=0.9 Significance level, α…

Q: Insurance companies are interested in knowing the population percent of drivers who always buckle up…

A: It is given that, x is 311 and n is 400.

Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

Q: 5.From a sample of 1,000 college students, 28% watch the Super Bowl game each year. Find the margin…

A:

Q: An accounting research firm asked 2100 accountants “Have you ever fudged the numbers before?” and…

A: The sample size is 2100 and 40% responded yes.

Q: a survey of 3088 adults aged 57 through 85​ years, it was found that 87.1​% of them used at least…

A: The formula for computing confidence interval is,  n is the sample size and P is the proportion.

Q: Out of 400 people sampled, 32 had kids. Based on this, construct a 95% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the sample number of people. From the…

Q: A medical director needs to know the proportion of patients who have a single bed in their room. A…

A: It is given that sample size (n) is 200 and p-hat value is 0.59.

Q: An accounting firm has 1200 clients. From a random sample of 120 clients, 110 indicated very high…

A: Given : An accounting firm has 1200 clients So,  Population size (N) = 1200 Sample size (n) = 120…

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Sample taken for ages 19 to 25 2253 men and 2629 women random sample In which 986 men and 923 women…

Q: You observe 60 customers at a coffee shop, and 82% of them tip. What is the 95% confidence interval…

A: Given : You observe 60 customers at a coffee shop, and 82% of them tip.

Q: Suppose a random sample of 142 graduates admissions officers were asked what role scores on…

A: Proportion is almost similar to the concept of probability. Proportion is a fraction of population…

Q: a recent study of 100 people in Burlingame found that 19 were obese.  Find the 90% confidence…

A:

Q: A Gallup Youth Survey in 2001 found that of 501 randomly selected teenagers in the U.S., 271 of them…

A: Given Total number of teenagers selected = 501Number of teenagers said who get along with their…

Q: At a large university in Conway, South Carolina, the Dean wants to know what proportion of students…

A: We have given thatn = 200x = 145Confidence level (c) = 99% = 0.99Significance level (α) = 1 - c =  1…

Q: Heather runs a successful lawn-mowing business. She would like to estimate the true mean amount of…

A: Given that  Sample size n =30 90 % confidence interval is (40 , 55)

Q: In a survey of 2255 randomly selected US adults (age 18 or older), 1787 of them use the Internet…

A: We want to calculate the 90% confidence interval for each of the following proportions

Q: A random variance survey of 495 adults found that 59 had diabetes. which of the following is a 98%…

A:

Q: In a survey of 2255 adults, 741 say they believe in UFOS. Construct a 95% confidence interval for…

A:

Q: What is the value of Z for this confidence interval?

A: Given,sample size(n)=14795no.of people who said yes=2219no.of people who said no =12576

Q: In a sample of 300 people, 154 said that they watched news on television. Find the 90% confidence…

A: According to the given information in this question We need to find the 90% confidence interval of…

Q: one with a 95% confidence level and the other with a 99.7% confidence level. Which interval is…

A: Confidence interval is probability, which refers that population parameter will fall within set of…

Q: 324 out of a simple random sample of 400 students hated their online math course. Find a 99%…

A: Given: Number of students that hated the online math course (y) = 324 Number of students (n) = 400…

Q: when 282 college students are randomly selected and surveyed, it is found that 109 own a car. find a…

A: It is given that sample size (n) is 282 and x is 109.

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Required conditions: n1>30 n2>30 n1*p1^>=10 n1*(1-p1^)>=10 n2*p2>=10 n2*p2^>=10

Q: Find the point estimate of the percentage of men who have red/green color blindness. b. Find a 90%…

A: Given that sample size n = 80 Number of men who have red/green color blindness, X = 7 At 90%…

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A:

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A:

Q: In a survey of 3332 adults aged 57 through 85​ years, it was found that 80.7​% of them used at least…

A:

Q: Find 90% confidence interval for the true proportion of all medical students who plan to work in a…

A: Given : Sample Size, n = 300 Number of successes, x = 30

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Required conditions: n1>30 n2>30 n1*p1^>=10 n1*(1-p1^)>=10 n2*p2>=10 n2*p2^>=10

Q: In a random sample of 184 college students, 97 had part-time jobs. Find the margin of error for the…

A: Given : Sample Size, n = 184 Number of successes, x = 97 confidence level,c=0.99

Q: Construct a 95% confidence interval for the proportion of college students who say they own their…

A: Given : n=410 , X=155  , α=0.05 We want to find the 95% confidence interval for the proportion of…

Q: 3. In a sample of 300 people, 154 said that they watched news on television. Find the 90% confidence…

A: Given : Sample size of people (n) = 300 Let X : No. of people from sample  who said they watched…

Q: f 260 employees selected randomly from one company, 18.46% of them commute by carpooling. Construct…

A: Given data, n=260 p=18.46% =0.1846 z-value at 98% confidence is Zc=2.326

Q: A recent survey of 349 people ages 18 to 29 found that 86% of them own a smartphone. Find the 99%…

A: The 99% confidence interval of the population proportion is obtained below as follows:   The formula…

Q: At one large college, 1867 out of the 2500 students surveyed said they plan to take another science…

A: The known values are, p^=1,867/2,500=0.7468, n=2,500. Using standard normal table, the critical…

Q: In a sample of 480 adults, 384 had children. Construct a 99% confidence interval for the true…

A: The random variable adults with children follow normal distribution. We have to construct 99%…

Q: You want to construct a 99% confidence interval for the proportion of retail stores that went out of…

A: The CI for the population proportion, p^±Zp^ (1-p^)nwhere, p^=sample proportion…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.