The New York Times conducted a nationwide poll of 1048 randomly selected 13- to 17-year-olds. to estimate the proportion of 13- to 17-year-olds who have a television in their room. We can consider the sample to be a simple random sample. Of these 1048 teenagers, 692 had a television in their room. Give a 95% confidence interval for the proportion of all people in this age group who had a TV in their room at the time of the poll, and interpret what your interval means in context.

4. At private college the achievement test is used for advanced study placement. Counselors selected a random sample of 144 students from the college and scored their tests by hand before sending them in for computer processing. For this sample, the mean was 450 and s = 29. Construct a 98% confidence interval for the mean.

in a town in nj we take a random sample of 100 residents. It turns out that 25% of the adult residents have degrees higher than high school diploma. Find a 90% confidence interval.

In a survey of 6000 high school students, 3230 read books during the summer break. Using these sample statistics, find a 99% confidence interval for the proportion p of all high school students that read books during the summer break.

You want to estimate the average difference in the number of complaints filed by women at work and the number of complaints filed by men at work.  You took an SRS of 7 businesses and collected the following data for number of complaints in a year: men 1 3 2 4 6 3 5 women 8 7 6 3 5 12 15   Create a 90% confidence interval for the average difference in the number of complaints filed by women at work and the number of complaints filed by men at work (in a year).  You must do this using table C.  If this is a 2 sample interval, be sure to specify who is population 1 and who is population 2.  If this is a matched pairs interval, be sure to state the order you subtracted your data.  Once you create your interval, give a sentence explaining the meaning of the interval (what the numbers in the interval mean, NOT the meaning of 95%) in context of this problem.  Round to any appropriate number of decimals.

In a survey, 545 college students are randomly selected and asked whether or not they own a car. Of those surveyed, it is found that 210 own a car. Use this data to find a 99% confidence interval for the true proportion of all college students who own a car.

Out of 3064 respondants, 919 of them said they have a dog. Using this data, compute a 95% confidence interval for the true proportion of people who own a dog.

A researcher wishes to estimate the proportion of college students who cheat on exams. A poll of 480 college students showed that 23​% of them​ had, or intended​ to, cheat on examinations. Find the​ 95% confidence interval for the population proportion. Round to four decimal places.