A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random sample by the National Institutes of Health included 2253 men and 2629 women in this age group. The survey found that 986 of the men and 923 of the women lived with their parents. Construct and interpret a 99% confidence interval for the difference in the true proportions of men and women aged 19 to 25 who live in their parents' homes. What conditions are met? (select all that apply) (Remember you check BOTH populations.) O 923 > 30 O 10(923) < all women aged 19 to 25 O 986 > 30 O 2253 > 30 O a random sample V 2629 > 30 O 986 > 10 O 10(2629) < all women aged 19 to 25 a random sample O 1267 > 10 O 1706 > 10 O 923 > 10 O 10(986) < all men aged 19 to 25 O 10(2253) < all men aged 19 to 25 O O

A doctor would like to estimate the mean difference in the number of hours of sleep for seniors in high school and seniors in college. To do so, he selects a random sample of 50 high school seniors from all high schools in his county. He also selects a random sample of 50 seniors from the colleges in his county. He would like to construct a 95% confidence interval for the true mean difference in the number of hours of sleep for seniors in high school and seniors in college. Are the conditions for inference met? Yes, all three conditions for inference are met. No, the random condition is not met for both samples. No, the 10% condition is not met for both samples. No, the Normal/large sample condition is not met for both samples.

57 out of 70 students said they were comfortable with “working in a workplace with a lot of activity,” and 38 out of 71 said they were comfortable with “doing group projects.” Find a 90% confidence interval for the difference between these two proportions.

In a sample of 1901 patients who underwent a certain type of surgery, 22% experiencedcomplications. Find a 90% confidence interval for the proportion of all those undergoingthis surgery who experience complications