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- (1) Data was collected for 187 randomly selected 10 minute intervals. For each ten-minute interval, the number of people entering the atrium of a large mall were recorded. The data is summarized in the table below. Number of guests Frequency 80 - 89 34 90 - 99 37 100 - 109 11 110 - 119 97 120 -129 8 What is the class width for this GFDT?. Class width =The clearness index was determined for the skies over Baghdad for each of the 365 days during a particular year. The following accompanying table summarizes the resulting data. Clearness Index Number of Days (frequency) 0.15 to <0.25 5 0.25 to <0.35 19 0.35 to <0.45 25 0.45 to <0.50 24 0.50 to <0.55 42 0.55 to <0.60 52 0.60 to <0.65 99 0.65 to <0.70 88 0.70 to <0.75 11 (a) Determine the relative frequencies and fill in the following table. (Round your answer to five decimal places if needed.) Class Intervals Frequency Rel. Frequency 0.15 to <0.25 5 0.25 to <0.35 19 0.35 to <0.45 25 0.45 to <0.50 24 0.50 to <0.55 42 0.55 to <0.60 52 0.60 to <0.65 99 0.65 to <0.70 88 0.70 to <0.75 11 (b) Draw the histogram. (Be careful here-the intervals do not all have the same width. Do this on paper. Your instructor may ask you to turn in this graph.)(c) Cloudy days are those with…5/6.2 I NEED TO SEE EXPLANATION PLEASE!!?
- • The total frequency all stems • Observations of the stem that has largest frequency Stem-and-leaf of Cl N - 82 Leaf Unit - 0.10 1 83 3 84 33 85 3. 86 ךרר 13 87 456789 23334556679 24 88 34 89 0233678899 (13) 35 90 0111344456789 91 0001112256688 22 92 22236777 14 93 023347 8. 94 2247 4 95 4 96 15 97 98 1 99 100 3 Q1 88.575 Median Q3 92.200 90.400 O a. Total frequency = 18 Observations on the largest frequency: 90.0, 90.1, 90.1, 90.1, 90.3, 90.4, 90.4, 90.4, 90.5, 90.6, 90.7, 90.8, 90.9 O b. Total frequency = 82 Observations on the largest frequency: 90.0, 90.1, 90.1, 90.1, 90.3, 90.4, 90.4, 90.4, 90.5, 90.6, 90.7, 90.8, 90.9 Oc Total frequency = 82 Observations on the largest frequency: 87.4, 87.5, 87.6, 87.7, 87.8, 87.9 Od. Total frequency cannot be determined by the present diagram Observations on the largest frequency: 90.0, 90.1, 90.1, 90.1, 90.3, 90.4, 90.4, 90.4, 90.5, 90.6, 90.7, 90.8, 90.9pA report gives the following observed trequencies : N= 1,000, (A) = 510, (B) = 490, (C) = 427, (AB) = 189, (AC) = 140, (BC) = 185. Show that there is some misprint or mistake of some sort and possibly the misprint.consists in dropping of 1 before 85 given as frequency of (BC).An estimate of the mean time taken by this group of workers is?
- Q.39) A patient's blood pressure for the first 15 days of the month was recorded as follows. Systolic BP (SBP): 126,137,119,129,136,138,135,140,127,130,128, 139,134,136,132 Diastolic BP (DBP): 89,94,93,95,90,87,92,88,90,91,86,84,89,91,93 (i) Create a data frame with the names of columns as "Day", "SBP", "DBP" (ii) Calculate the max-SBP and max-DBP using R statistical function (iii) Calculate mean-SBP and mean-DBP using R statistical function (iv) Create an appropriate chart for the above data set.The table below shows a frequency distribution of the lifetimes of electronic tubes produced at a factory, determine the Arithmetic Mean for lifetimes of the tubes. * Lifetime Number of (hours) 300-399 Electronic Tubes 14 400-499 46 500-599 58 600-699 76 700-799 68 800-899 62 900-999 48 1000-1099 22 1100-1199the monthly rents in dollars paid by 8 people are given below. 840,860,900,930,985,1035,1075,1095 suppose one of the people move her rent changes from 840 to 880? what happends to the mean ? what happends to the medium?
- The following table gives partial output of a survey involving students in Australia and Japan. It contains the number of students pursing STEM, HASS and Other studies as their undergraduate degree in both countries. Some sub-totals are given. Each X denotes an unknown value. The value of each X may be different, Australia |Jаpan Total STEM X X 107 HASS X 92 Other X Total 131 146 You are performing a Chi Square test for homogeneity, that is you're testing if the proportions across different populations are equal. If the proportions across the two countries are the same, what is the expected value of students doing Other studies in Japan? Give your answer to 2 decimal places.The relative error when 2.01239572 is estimated by 2.01237689 is Blank 1. (Answer must be in 8 decimal places) Blank 1 Add your answerWhich one is wrong about Chi Square Test Select one: O a. Degree of freedom required to check critical value b. Individual frequency should be minimum 5 O c. Not applicable for study of proportions Od. Total of frequencies should be at least 50