The magnitude of the angular momentum of a 625 g basketball (radius 22.9 cm) spinning at 11 rev/s on an axis through its center of mass is approximately...   A 0.24 kg m2 s-1   B 0.36 kg m2 s-1   C 0.14 kg m2 s-1   D 38 kg m2 s-1

An ice skater is spinning about a vertical axis with arms fully extended. If the arms are pulled in closer to the body, in which of the following ways are the angular momentum and kinetic energy of the skater affected? A. L increases, K increases B. L increases, K remains constant C. L remains constant, K increases D. L remains constant, K remains constant

1. 0 10 20 ESSE 30 x(cm) Four masses are arranged as shown. M₁-3 kg at (0,0)cm. M3-3 kg at (20,0)cm. M₂=5 kg at (10,0)cm. M4-5 kg at (30,0)cm. The masses are connected by a light rod of negligible mass. a.) Calculate the moment of inertia if the masses rotate around the y-axis (M₁ is the center of rotation). b.) The object is rotating about the y-axis with w = 6 rad/s. Find the tangential velocities of each separate mass. Show that the sum of the kinetic energies of the individual masses equals the rotational energy of the entire system:Σ-1m₁ v² = 1/1/1w². c.) If 0.5 J of work is done to this system, what is the new angular velocity, w? d.) Calculate the moment of inertia of the system if it now rotates about an axis that passes through mass #3, parallel to the y-axis. e.) What is the rotational kinetic energy of the system if it rotates about M3 with w = 6 rad/s?

A playground merry-go-round with a mass of 145 kg and a radius of 1.9 m is rotating with an angular frequency of 0.42 rev/s. -What is the magnitude of its angular velocity, in radians per second, after a 17 kg child gets onto it by grabbing its outer edge? The child is initially at rest.

Two small 0.55-kg masses are attached to opposite ends of a very lightweight rigid rod 0.7 m long. The system is spinning in a horizontal plane around a vertical axis perpendicular to the rod located halfway between the masses. Each mass is moving in a circle of radius 0.35 m at a speed of 0.85 m/s. What is the total angular momentum of this system? kg-m²/s Need Help? Read It

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3. A playground has a small merry-go-round with radius 1.00 m. It's moment of inertia is 125 kgm2. A small child with mass 35.0 kg runs at a velocity of 2.50 m/s along a path tangent to the outer rim of the stationary merry-go-round and jumps on. Calculate (a) the magnitude of the angular momentum of the child about the axis of rotation of the merry-go-round, and (b) the angular speed of the combined merry-go-round plus child after the child jumped on. You may assume the child is a point mass.

A 0.02 kg mass red object (bead) is moving at a speed of 10.0 m/s when it sticks to the edge of a uniform solid cylinder. The cylinder is free to rotate about its axis through its center and has a mass of 0.5 kg , a radius of 0.25 m and is initially at rest. I = 1/2MR​2^2 a) What is the angular velocity of the system after the collision? b) How much kinetic energy is lost in the collision? c) If the angular position of the Cylinder varies as θ(t)=3.2t-t​^2 ​find the centripetal acceleration of the red object (bead). d) A cord is now wrapped around the cylinder. Use the work energy theorem to find the angular velocity of the cylinder after 5.0m of cord have been removed by a 40N Force. e) If the 40N force on the cord is replaced by a 40-N weight, what is the angular velocity of the cylinder after 5.0m of cord has unwound?

F18-4. The 50-kg wheel is subjected to a force of 50 N. If the wheel starts from rest and rolls without slipping, determine its angular velocity after it has rotated 10 revolutions. The radius of gyration of the wheel about its mass center G is kg = 0.3 m. P = 50 N 04 m 30°

The rotation of the planet Mercury is a little strange compared to Earth. It rotates on its axis very slowly; one rotation takes 56.85 earth days. Assuming Mercury is a perfect sphere of mass 3.29*1023 kg and radius 2440 km, calculate its angular momentum. a) 1.0*1030 kg.m2/s b) 1.0*1028kg.m2/s          c) 1.0*1032 kg.m2/s Calculate its rotational KE. a) 1.4*1023 J                          b) 3.4*1021 J                                   c) 6.4*1023 J